Answer:
∛27 = 3
Step-by-step explanation:
A radical is simply a fractional exponent: ![a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=a%5E%7B%28%5Cfrac%7Bm%7D%7Bn%7D%29%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Hence, ∛27 = 
Since 27 = 3³, then:
You could rewrite ∛27 as ∛(3)³.
![\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E%7B%283%29%7D%20%7D%20%3D%203%5E%7B%5B%283%29%2A%28%5Cfrac%7B1%7D%7B3%7D%29%5D%7D)
Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.
Therefore, ∛27 = 3.
Answer:
x ≈ 1.32, x ≈ - 5.32
Step-by-step explanation:
Given
x² + 4x - 7 = 0 ( add 7 to both sides )
x² + 4x = 7
To complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(2)x + 4 = 7 + 4
(x + 2)² = 11 ( take the square root of both sides )
x + 2 = ± 
( subtract 2 from both sides )
x = - 2 ± 
Thus
x = - 2 - ≈ - 5.32 ( to 2 dec. places )
x = - 2 + ≈ 1.32 ( to 2 dec. places )
Y = -5x - 4
switch x and y and solve for y
x = -5y - 4
x+4 = -5y
(x+4)/ -5 = y^-1 ( the inverse)
The equation would be (100-10) ÷30 your answer would be 3
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