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Ronch [10]
3 years ago
5

Need help ASAP AND SHOW WORK PLEASE !! 40 points

Mathematics
2 answers:
yanalaym [24]3 years ago
7 0

Answer:

<h3>Area=20</h3><h3>whereas, Perimeter=21</h3>

Vinvika [58]3 years ago
5 0
Area = 20
perimeter = 21

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In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?
valina [46]
To solve this problem, we need to know that 
arc length = r &theta;  where &theta; is the central angle in radians.

We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, &theta;
Rearrange equation at the beginning,
&theta; = (arc length) / r = 4pi / 6 = 2pi /3

Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
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3 years ago
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16 mm = cm 4 7/8 13/4
Alekssandra [29.7K]

Answer:

1 cm  6mm

Step-by-step explanation:

10mm=1cm

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3 years ago
There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the
vfiekz [6]

Answer:

Probability that the result is a multiple of 4 or a multiple of 3=  0.428

Step-by-step explanation:

The spinner is divided into 14 equal areas.

Probability of an event=\frac{number of favourable outcomes}{total number of outcomes}

For favourable events,result should be a multiple of 3 or 4.

All the possible outcomes are=1,2,3,4,5,6,7,8,9,10,11,12,13,14

  • Multiples of 3=3,6,9,12
  • Multiples of 4=4,8,12

Hence the favourable outcomes are=3,4,6,8,9,12

Number of favourable outcomes=6

Total number of outcomes=14

Probability=\frac{6}{14}

                 =0.428

5 0
3 years ago
How much millimeters is in one cup
Orlov [11]
In one U.S cup, there are 236.588 milliliters. (No such thing as milli"meters" in a cup). 
7 0
3 years ago
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Point a pq and r are collinear on pr and pq: pr =2/3. P is located on the origin q is located at (x,y) and r is located at (-12,
dybincka [34]

The values of x and y are  8 and 0 respectively.

<em><u>Explanation</u></em>

As 'p' is located at (0,0) and 'r'  is located at (-12,0) , that means both 'p' and 'r' are on the x-axis.  So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq' = \sqrt{(x-0)^2 +(0-0)^2}= \sqrt{x^2}= x

and length of  'pr'  = \sqrt{(-12-0)^2+(0-0)^2}= \sqrt{144}=12

Given that,   pq : pr =2/3

So....

\frac{x}{12} =\frac{2}{3}\\ \\ 3x=24\\ \\ x= \frac{24}{3}=8

Thus, the values of x and y are  8 and 0 respectively.

8 0
3 years ago
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