So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.
You know that you have
90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle
sin19 = x/15
15sin19 = x
x = 2.2
Now do Pythagoras c^2-b^2=a^2
a = 14.8
So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)
Hi! I will try my best to answer your question, the wording provided is unclear.
If the 10% of the original cost of something is $1.50, then the total cost is $15.00.
Assuming this is the discounted price, which would be 90% of the original cost, the original cost would be $16.67.
Duck iimwisis is the time is the last day to a week or two or three days of February and February
Step-by-step explanation:
This problem bothers on the density of substances
Given data
Mass of substance m= 16kg
Volume of substance v = 2L
the equation that relates the volume. V. to the mass, m is the expression for density
ρ= mass/volume
Substituting our given data
ρ= 16/2= 8kg/L
Using the density calculated above we can get the volume liters, of 128kg of liquid
8= 128/v
v=128/8
v= 16L
The volume is 16L
The density of a substance is expressed as the mass per unit volume
Answer:
answer is 52 cm
Step-by-step explanation:
BA = 17, BF = 6, and CG = 9
triangle sides BF and BH are congruent because they are tangent lines along the same curve
BH is equal to 6 since BF is equal to 6
this applies to CG and CF and AG and AH
CG is equal to 9
so CF is equal to 9
now we add 6 + 9 for the measurement of side CB
CB = 15
now we do the same for the other two sides
we already know BA = 17 so we subtract it from BH = 6 to find the measurement of AH
AH is equal to 11 and is tangent across the same curve as AG
AG = 11
now we add AG to CG
11 + 9 = 20
now we know all the side lengths
CB + BA + AC = Perimeter
15 + 17 + 20 = 52
Perimeter of triangle BCA = 52
I don't know why I went through all the trouble if I know no one is going to see this :'(. I just thought the other guy gave the wrong reasons
