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Katarina [22]
2 years ago
10

7. The amount of time it takes an athlete to complete a Ninja warrior course is normally distributed with mean 8.25 minutes and

standard deviation 0.4 minutes.
What percent of athletes complete the course in less than 7.5 minutes?
A00304
B. 05134
01342
0.3892
Mathematics
1 answer:
otez555 [7]2 years ago
4 0
The answer is c I think
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The population of a country grows exponentially at a rate of 1% per year. If the population was 35.7 million in the year 2010, t
Lady_Fox [76]

Answer:

37.52 million

Step-by-step explanation:

using,

A = A'(1+R/100)ⁿ............................. equation 1

Where A = population size in 2015, A' = Initial population, R = rate in percentage, n = number of times between 2010 and 2015.

Given: A' =35.7 million, R = 1%, n = 5.

Substitute these values into equation 1

A = 35.7(1+0.01)⁵

A = 37.52 million.

Hence the size of the population of the country in the year 2015 is 37.52 million

7 0
2 years ago
• The shortest side of a triangle is 8 centimeters long. The longest side is 8 cm longer than the
gizmo_the_mogwai [7]
The shortest side is 9, longest is 17 of the triangle IS NOT a 90 degree triangle
5 0
3 years ago
-3/7 is equivalent to what other fraction
liubo4ka [24]

Answer:

Step-by-step explanation:

6/14 = -9/21 = -12/28 = -15/35 = -18/42 = -21/49 = -24/56 = -27/63 = -30/70 = -33/77 = -36/84 = -39/91 = -42/98 = -45/105 = -48/112

6 0
3 years ago
Lemme get some help plz
enot [183]

Answer:

6(8x-2)

48x- 12 (this is the answer)

Step-by-step explanation:

to do those, you use the distributive property, which is taking the number outside the parenthesis and multiplying it by everything inside of it

4 0
2 years ago
In a recent Super Bowl, a TV network predicted that 50 % of the audience would express an interest in seeing one of its forthcom
coldgirl [10]

Answer:

z= -0.968

We can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that  they would watch one of the television shows not differs from 0.5 or 50% .  

Step-by-step explanation:

1) Data given and notation n  

n=106 represent the random sample taken

X=48 represent the people who says that  they would watch one of the television shows.

\hat p=\frac{48}{106}=0.453 estimated proportion of people who says that  they would watch one of the television shows.

p_o=0.5 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that 50% of people who says that  they would watch one of the television shows.:  

Null hypothesis:p=0.5  

Alternative hypothesis:p \neq 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.453 -0.5}{\sqrt{\frac{0.5(1-0.5)}{106}}}=-0.968  

4) Statistical decision  

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided, but we can assume \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

So based on the p value obtained and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that  they would watch one of the television shows not differs from 0.5 or 50% .  

6 0
3 years ago
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