Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
Answer:
its correct bro ;) click next
You can write any decimal as a precent by moving the decimal 2 places to the right so
0.51 = 51%
5.1% < 51%
5.1% < 0.51
or, any precent can be written as a decimal by moving the decimal points two point to the left so
5.1% = 0.051
0.051 < 0.51
5.1% < 0.51
Answer:
Ok, so I hope I understood the task. Here goes nothing
Step-by-step explanation:
So, first we calculate the area of the big rectangle,
(√63+√28)*√45 = 15√35
Then we calculate the area of the small rectangle
√7*√5 = √35
Then we do this to get the area left
15√35 - √35 = 14√35
Then we take
That should explain it
