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ivann1987 [24]
3 years ago
9

A) I only B)I and II only C)III and IV only D)I,III,and IV only

Mathematics
1 answer:
vampirchik [111]3 years ago
5 0
The answer would be C because linear relationships is straight lines

Hope this helps

Have a great day/night
You might be interested in
Whats 6÷796 with remaimder
cupoosta [38]
The answer was : <span>0.00753768844 I did have to use a calculator for that and I hope that was ok. ;)</span>
8 0
3 years ago
How do you do this (the first one)? i've been sitting trying to do this for literally half an hour.
joja [24]
Spain = 140
Italy = 40
France = 60
U.S.A = 120
total = 18,000,000

Spain : 140/360 = 39%.....0.39(18,000,000) = 7,020,000
Italy : 40/360 = 11%....0.11(18,000,000) = 1,980,000
France : 60/360 = 17%....0.17(18,000,000) = 3,060,000
U.S.A : 120/360 = 33%...0.33(18,000,000) = 5,940,000



6 0
3 years ago
In Happyville, the ideal family has four children, at least two of which are girls. If you randomly select a Happyville family t
sleet_krkn [62]

Answer:

0.3125 = 31.25% probability that it is not ideal.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it is a girl, or they are not. The probability of a child being a girl is independent of any other child. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.5 probability of a children being a girl:

This means that p = 0.5

If you randomly select a Happyville family that has four children, what is the probability that it is not ideal?

Not ideal is less than two girls, so this is P(X < 2).

Four children means that n = 4. So

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.5)^{0}.(0.5)^{4} = 0.0625

P(X = 1) = C_{4,1}.(0.5)^{1}.(0.5)^{3} = 0.25

P(X < 2) = P(X = 0) + P(X = 1) = 0.0625 + 0.25 = 0.3125

0.3125 = 31.25% probability that it is not ideal.

7 0
2 years ago
66 points! for if you get this right 99 kids go race go karts for a all day pass is $56 per kid then they play arcade games at a
Romashka-Z-Leto [24]

The total amount that was spent is $6099

<h3>How to determine the total amount that was spent?</h3>

The given parameters are

Number of kids = 99

Pass = $56 per kid

Arcade game = $555

The total amount that was spent is calculated as

Total = Number of kids * Pass + Arcade game

So, we have

Total = 99 * 56 + 555

Evaluate the expression

Total = 6099

Hence, the total amount that was spent is $6099

Read more about expressions at

brainly.com/question/723406

#SPJ1

7 0
1 year ago
I need help on the steps of solving this problem?.<br> divide 4950 and 75
ryzh [129]

Answer:

4950/75 = 66

Step-by-step explanation:

Use a calculator to help you out!

4 0
3 years ago
Read 2 more answers
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