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dmitriy555 [2]
4 years ago
12

John has two different sugar syrups. Syrup A is 2 parts of sugar and 8 parts of water, and Syrup B is 3 parts of sugar and 5 par

ts of water. How much of each should john mix together to get 280 quarts of syrup that is 3 parts sugar and 7 parts water.
Mathematics
2 answers:
Juli2301 [7.4K]4 years ago
7 0

Answer:

Volume of syrup A = 120 quarts

Volume of syrup B = 280 - 120 = 160 quarts .

Step-by-step explanation:

Syrup A : 2 parts sugar , 8 parts of water .

Total = 10 parts

Syrup B : 3 parts sugar , 5 parts of water .

Total = 8 parts .

Mixture required 280 quarts , 3 parts sugar , 7 parts water

In 280 quarts , sugar = 280 x 3  / ( 3 + 7 )

sugar = 84 parts

Let volume of syrup A be x , volume of syrup B = 280 - x

sugar A =  2 x / 10 = 0.2 x

sugar B = 3 ( 280 - x ) / 8 = .375 ( 280 - x )

Total sugar =  .2 x + .375 ( 280 - x ) = 84 .

.2 x + 105 - .375 x = 84

105 - 84 = .375 x - .2 x = .175 x

.175 x = 21

x = 21 / .175 = 120

Volume of syrup A = 120 quarts

Volume of syrup B = 280 - 120 = 160 quarts .

sweet-ann [11.9K]4 years ago
6 0

Answer:

120 and 160

Step-by-step explanation:

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Step-by-step explanation:

Given

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3 years ago
Please help me with these questions , thank you​
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Answer:

1. 4x^{3} + 26x² + 4x - 48

2. 2x^{3} - 23x² + 60x - 32

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Step-by-step explanation:

To multiply polynomials, simply distribute whatever's outside the largest set of parenthesis, then combine like terms.

1) Distribute the parenthesis (x + 6):

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2) Distribute the parenthesis (x - 8):

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x^{5} + 7x^{3} - 4x + 2x^{4} + 14x² - 8

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x(2x^{6} - 7x^{5} + 3)  +  4(2x^{6} - 7x^{5} + 3)

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hope this helps!

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