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sladkih [1.3K]
3 years ago
5

Pls helping with this mathematics quiz

Mathematics
1 answer:
Trava [24]3 years ago
5 0

1.  surface area?

2. 806

3. 15.7

4. surface area?

5. 50.3

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Which ratio is equivalent to 12 : 32?<br> A. 48/128<br> B. 28/63<br> C. 7/15<br> D. 48/64
Sladkaya [172]
A because 12*4=48 and 32*4=128
4 0
4 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

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x^7+x^6+x^5-x^4-x^3-x^2-x+1

Step-by-step explanation:

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Answer:

4

Step-by-step explanation:

3x-12=24

-12 to both sides

3x-12-12=24-12

3x=12

3x/3=12/3x

x=4

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