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4 years ago

Someone please help me with number 13

Mathematics

1 answer:

wolverine [178]4 years ago

8 0

X = 60 degrees.

This is because the perimeter of a triangle MUST add up to 180 degrees. Since this is an equilateral triangle (meaning each side is the same length) and each side is 60 degrees, 180-120 (120 because 60 x 2 = 120) = 60.

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An electric company charges an initial monthly fee for service and a fixed rate per kilowatt-hours (kWh) used. This table shows

Vlada [557]

Here we are required to determine the initial monthly fee charged by the electric company.

The initial fee charged by the electric company is; C = $10

To solve this, we need to evaluate the slope and intercepts of the equation of the straight line graph of the relation.

y = mx + c.

where m = slope of the relation.

and c = intercept = the initial fee charged by the electric company.

y = Monthly charge at each time.

x = Usage

To find the slope;

m = (y2 - y1)/(X2 - x1)

m = (28 -22)/(150 - 100)

m = 6/50

m = 0.12.

By substituting m into the equation y = mx + c, alongside a pair of values of usage and monthly charge, we can obtain the intercept, c (i.e the initial fee charged).

Therefore, m = 0.12 , y = 82 and X = 600;

we then have;

82 = 0.12(600) + c.

C = 82 -72

C = $10.

Therefore, the initial fee charged by the electric company is; C = $10.

Read more:

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8 0

3 years ago

A model rocket is launched from the top of a building. The height(in meters) of the rocket above the ground is given by h(t)=-6t

Shalnov [3]

Answer:

Step-by-step explanation:

I don't know if you are a calculus student, but since calculus is the easiest way to solve this, that's what I used. The position equation is

$s(t)=-6t^2+24t+14$

and the velocity function, the first derivative, is

$v(t)=-12t+24$

From Physics, you should know that the velocity of an object is 0 at its highest point. That means that if we sub in a 0 for the velocity and solve for t, we find the time at which the object is at its highest point. That is:

$0=-12t+24$ and

$0=-12(t-2)$

By the Zero Product Property,

-12 definitely does not equal 0, so that means that

t - 2 = 0 and

t = 2 seconds.

So at 2 seconds, the object is at its highest point. Go back to the position function now and sub in a 2 for t to find the height of the object at 2 seconds.

$s(2)=-6(2)^2+24(2)+14$ so