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3 years ago

HELP NEEDED ASAP GIVING BRAINLIEST!!

Physics

2 answers:

daser333 [38]3 years ago

4 0

Asteroid or exploding planet.

nikitadnepr [17]3 years ago

3 0

Exploding planet or astroifd

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Three liquids are at temperatures of 6 ◦C, 23◦C, and 38◦C, respectively. Equal masses of the first two liquids are mixed, and th

kupik [55]

The equilibrium temperature is T13=3.12 ◦C

<u>Explanation:</u>

<u>Given </u>

The temperature of liquids: T1=6◦C, T2=23◦C, T3=38◦C

The temperature of 1+2 liquids mix: T12= 13◦C.

The temperature of 2+3 liquids mix: T23=26.8 ◦C.

The temperature of 1+3 liquids mix: T13= ??

<u>1.When the first two liquids are mixed:</u>

mC1(T1-T12)+mC2(T2-T12)=0
C1(6-13)=C2(23-13)=0
7C1=10C2
C1=1.42C2

<u>2.When the second and third liquids are mixed</u><u>:</u>

mC2(T2-T23)+mC3(T3-T23)=0
C2(23-26.8)=C3(38-26.8)=0
3.8C2=12.8C3
C2=3.36C3

<u>3.When the first and third liquids are mixed:</u>

mC1(T1-T13)+mC3(T3-T13)=0
C1(6-T13)+C3(38-T13)=0
C1=1.42C2 C2=3.36C3
C1=1.42C2(3.36C3)
C1=4.77C3
C1(6-T13)+C3(38-T13)=0
4.77C3(6-T13)+C3(38-T13)=0
By solving the equation we get,
T13=3.12 ◦C
The equilibrium temperature is T13=3.12 ◦C

<u></u>

7 0

3 years ago

A piece of string 2 meters and has a mass of 5g. On one end of the string hangs a 200 g mass. Find the tension of the string and

viktelen [127]

Explanation:

It is given that,

Length of the string, l = 2 m

Mass of the string, $m=5\ g=5\times 10^{-3}\ kg$

Hanged mass in the string, $m'=200\ g=0.2\ kg$

1. The tension in the string is given by :

$T=m'g$

$T=0.2\times 9.8$

T = 1.96 N

2. Velocity of the transverse wave in the string is given by :

$v=\sqrt{\dfrac{T}{M}}$

m = M/l

$v=\sqrt{\dfrac{Tl}{m}}$

$v=\sqrt{\dfrac{1.96\times 2}{5\times 10^{-3}}}$

v = 28 m/s

Hence, this is the required solution.

4 0

3 years ago

A college student likes to take her books to class by placing them in a box and pulling the box around behind her. She pulls on

just olya [345]

Answer:

It would result an a negatice answer.

Explanation:

The accelarion should be pulled as a kite not a box :) columbus said that musical stuff no just no

Hope this helps!!

- Katty queen

8 0

3 years ago

S A block of mass M is connected to a spring of mass m and oscillates in simple harmonic motion on a frictionless, horizontal tr

cestrela7 [59]

The kinetic energy of this block-spring when the block has a speed (v) is given by K.E = 1/2 × (M + m/3)v².

<h3>What is kinetic energy?</h3>

Kinetic energy can be defined as a form of energy that is possessed by a person due to its motion or change in speed (acceleration).

<h3>How to calculate kinetic energy?</h3>

Mathematically, kinetic energy can be calculated by using this formula:

K.E = 1/2 × mv²

Where:

K.E represents the kinetic energy.

m represents the mass.

v represents the speed or velocity.

Since the mass of a segment of this spring is dm = (m/l) dx, the kinetic energy for each of its segment would be given by:

dK = 1/2 × (dm)Vx²

This ultimately implies that, the kinetic energy of this block-spring when the block has a speed (v) is given by:

K.E = 1/2 × Mv² + 1/2 × ¹∫₀((x²v²/l²)m/ldx

K.E = 1/2 × (M + m/3)v².

Read more on kinetic energy here: brainly.com/question/15848455

#SPJ4

6 0

2 years ago

How fast would a(n) 75 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 390 m/s

nata0808 [166]

Answer:

Explanation:

½(75)v² = ½(0.008)390²

v² = (0.008)390²/75

v² = 16.224

v = 4.027...

v = 4.0 m/s

6 0

3 years ago