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sp2606 [1]
3 years ago
11

This is the question please help asap

Physics
1 answer:
MAXImum [283]3 years ago
6 0

I am not sure of this, but it is either the third option or the last option.

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How can you tell there is only one atom of oxygen in H2O?
kow [346]

Answer:

For H2O, there is one atom of oxygen and two atoms of hydrogen. A molecule can be made of only one type of atom. In its stable molecular form, oxygen exists as two atoms and is written O2. to distinguish it from an atom of oxygen O, or ozone, a molecule of three oxygen atoms, O3.

Explanation:

4 0
3 years ago
One problem with weight training as a way to improve overall health is that the results of a weight-training program are not mea
Ede4ka [16]

One problem with weight training as a way to improve overall health is that the results of a weight-training program are not measurable.

B.False

5 0
3 years ago
Read 2 more answers
An inductor is connected to a 26.5 Hz power supply that produces a 41.2 V rms voltage. What minimum inductance is needed to keep
alexira [117]

Answer:

The minimum inductance needed is 2.78 H

Explanation:

Given;

frequency of the AC, f = 26.5 Hz

the root mean square voltage in the circuit, V_{rms} = 41.2 V

the maximum current in the circuit, I₀ = 126 mA

The root mean square current is given by;

I_{rms} = \frac{I_o}{\sqrt{2} } \\\\I_{rms}  = \frac{126*10^{-3}}{\sqrt{2} }\\\\I_{rms}  =0.0891 \ A

The inductive reactance is given by;

X_l = \frac{V_{rms}}{I_{rms}} \\\\X_l= \frac{41.2}{0.0891}\\\\X_l = 462.4 \ ohms

The minimum inductance needed is given by;

X_l = \omega L\\\\X_l = 2\pi  fL\\\\L = \frac{X_l}{2\pi f}\\\\L = \frac{462.4}{2\pi *26.5}\\\\L = 2.78 \ H

Therefore, the minimum inductance needed is 2.78 H

7 0
3 years ago
Help me please !!!!!
bezimeni [28]

Answer:

confounding cause they had exposure to many programmes

8 0
3 years ago
Read 2 more answers
Gulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells.
kumpel [21]

Answer:

v = 17.71 m / s

Explanation:

We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity

                v² = v₀² - 2 g (y -y₀)

                v² = 0 - 2g (y -y₀)

when it hits the stone the height is zero and part of the height of the seagull I

              v² = 2g y₀

              v = Ra (2g i)

let's calculate

              v =√ (2 9.8 16)

              v = 17.71 m / s

8 0
3 years ago
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