-- below the horizon
-- clear sky
<span>buzzed, droned, jangled, reverberated.</span>
Answer:
Force of 
Kgm/s^2 must be applied to the piston to raise oil to a height of 6.0 m
Explanation:
As we know,
Pressure is the force per unit area
Or 
Force 
Pressure is the product of density, gravitational constant and height
Force
Kgm/s^2
Fnet = Fg sin 30 - Ff
ma = mg sin 30 - mew Fg cos 30
ma = mg sin 30 - mew mg cos 30
a = g sin 30 - mew gcos30
a - g sin 30 = - mew g cos 30
mew = -(a - g sin30)/(g cos 30)
mew = -(3m/s2 - 9.81sin30)/(9.81 cos 30)
mew = 0.22
