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svetoff [14.1K]
3 years ago
5

The area of a rectangle is 36 square centimeters and its length is 9 centimeters

Mathematics
1 answer:
Andrei [34K]3 years ago
8 0
A) 4 cm
B) 9 cm x 12 cm
C) 108 cm
You might be interested in
Qt + a = -1 <br><br> when q = 3 and t = 4
Pachacha [2.7K]

Answer:

a=-13

Step-by-step explanation:

We can use substitution to find the value of a:

qt+a=-1

3(4)+a=-1

12+a=-1

a=-13

Hope this helps :)

5 0
3 years ago
Help with these precalculus problems, please.
likoan [24]
Yay, easy peasy, nice refresher


53. evaluate for x=infinity
we get 100/(infiniy^2-5) which is basically 100/infinity which is a very small number so about 0



54.
vertical assemtotes, neato
that is where the denomenator equals 0
but wait, simplify first
ok, fraction is simplified (anything factored out would be a hole)
so set the denom to 0 and solve
x^2-5=0
(x-√5)(x+√5)=0
x=-√5 and √5
vertical assemtotes at x=-√5 and x=√5




55. horizontal assemtotes
for the function p(x)/f(x)

if p(x) has lower degree than f(x) then y=0 is the horizontal assemtote

if p(x) has equal degree to f(x) then divide the leading coefients of p(x) and f(x)

if p(x) has greater degree than f(x) then we got slant assemtotes

100/(x^2-5)
100 has lower degree than x^2
y=0 is the horizontal assemtote



56. evalate for x=-5
we get -150/-10=150/10=15
the limit is 15



57. that negative on the right side means that we must approach it from the left
let's see if we can factor out the denomenator
nope
so go and evaluate values like 4, 4.5, 4.9, etc, approaching x=5 from the left
we keep getting smaller and smaller valuse
this make sense because as x approaches 5, we get 30(c)/(c-5) where c is close to 5, and as c appraoches 5 very close, the top part is appraoching 150 but the bottom approaches a very small negative number, and if we do something like 150/-0.00000000001, we get a very negative number
the limit is negative infinity

alternately, you could figure that there is a vertical assemtote at x=5 so we can see that if we aproximaate closer and closer values, we get smaller values. so from what we know about assemtotes, expecially vertical ones, we say that it approaches negative infinity




58.
evalauating we get infintity/inifinty, not helpful
hmmm, is there a horizontal assemtote to help us?
the degree of top is higher so we got a slant assemtote
the only way is to use long division to divide the top by the bottom (see attachment)
we get
\frac{1}{2}x-\frac{1}{4}+\frac{\frac{1}{4}}{2x+1}
the slant assemtote is y=\frac{1}{2}x-\frac{1}{4}
as you can see, as x approaches infinity, y also will approach infinity











ANSWERS:
53. 0
54. VA is x=-√5 and x=√5
55. HA is y=0
56. the limit is 15
57. the limit is -∞
58. the limit is ∞

6 0
3 years ago
A quality analyst wants to construct a sample mean chart for controlling a packaging process. He knows from past experience that
rosijanka [135]

Using it's concept, it is found that the sample mean package weight for Thursday is of 19 ounces.

<h3>What is the mean of a data-set?</h3>

The mean of a data-set is given by the <u>sum of the observations divided by the number of observations</u>.

For Thursday, the package weights in ounces are given by: {18, 19, 20, 19}.

Hence, the sample mean in ounces is of:

M = (18 + 19 + 20 + 19)/4 = 19.

More can be learned about the mean concept at brainly.com/question/24628525

3 0
2 years ago
3 semicircles are connected to 3 sides of a square. each side of the square measures 4 centimeters. what is the area of the comp
puteri [66]

The area of the composite figure  with 3 semicircles connected to 3 sides of a square is (6π+16)cm^{2}.

<h3 /><h3>What is a semicircle?</h3>

A semicircle is a plane shape that is a part of a circle divided into two equal parts through its diameter.

Analysis:

Since the semicircles are connected to 3 sides of a square 4cm, the diameter of the semicircle is 4cm.

Radius of semicircle = 4/2 = 2cm

Area of a semicircle = πr^{2}/2 = \pi(2)^{2}/2 = 2πcm^{2}

For three semicircles = 3 x 2πcm^{2} = 6πcm^{2}

Area of square = s^{2} = (4)^{2} = 16cm^{2}

Area of composite figure  = Area of 3 semicircles + area of square

Area of composite figure = (16 + 6π)cm^{2}

In conclusion, the area of the composite figure is  (16 + 6π)cm^{2}.

Learn more about  area of plane shapes: brainly.com/question/20475473

#SPJ4

5 0
2 years ago
Can 1,2,5 be the lengths of a triangle
ioda
No the length of a triangle 2 smaller sides has to be greater than the sum of the other longer side
3 0
3 years ago
Read 2 more answers
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