The relation you have shown is not a function.
In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.
One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.
Answer:
x = 10
Step-by-step explanation:
2x/3 + 1 = 7x/15 + 3
<em><u>(times everything in the equation by 3 to get rid of the first fraction)</u></em>
2x + 3 = 21x/15 + 9
<em><u>(times everything in the equation by 15 to get rid of the second fraction)</u></em>
30x+ 45 = 21x + 135
<em><u>(subtract 21x from 30x; subtract 45 from 135)</u></em>
9x = 90
<em><u>(divide 90 by 9)</u></em>
x = 10
<h2>
Another solution:</h2>
2x/3 + 1 = 7x/15 + 3
<u><em>(find the LCM of 3 and 15 = 15)</em></u>
<u><em>(multiply everything in the equation by 15, then simplify)</em></u>
10x + 15 = 7x + 45
<u><em>(subtract 7x from 10x; subtract 15 from 45)</em></u>
3x = 30
<em><u>(divide 30 by 3)</u></em>
x = 10
I'm not real sure if this is right but I did my best
Answer:
they are both 0 since they would not appear on a graph
Step-by-step explanation:
