Help please will mark you brainliests

What is α, the probability of a Type I error if the null hypothesis, H0, is: Carmin believes that her chemistry exam will only c

baherus [9]

Answer:

The probability of falling into a type I error, when testing a hypothesis test, consists of:

Probability of rejecting the null hypothesis when, in reality, this hypothesis is true.

Probability of rejecting the null hypothesis when, in reality, this hypothesis is true, is:

Probability of Affirm that Chemistry exam will NOT cover only chapters four and five, since the Chemistry exam will cover only chapters four and five.

That is, alpha is the probability that Carmin decides to study additional chapters, unnecessarily.

Step-by-step explanation:

8 0

3 years ago

The manager of a computer retails store is concerned that his suppliers have been giving him laptop computers with lower than av

34kurt

Answer:

Probability that the 50 randomly selected laptops will have a mean replacement time of 3.1 years or less is 0.0092.

Yes. The probability of this data is unlikely to have occurred by chance alone.

Step-by-step explanation:

We are given that the replacement times for the model laptop of concern are normally distributed with a mean of 3.3 years and a standard deviation of 0.6 years.

He then randomly selects records on 50 laptops sold in the past and finds that the mean replacement time is 3.1 years.

Let M = sample mean replacement time

The z-score probability distribution for sample mean is given by;

Z = $\frac{ M-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean replacement time = 3.3 years

$\sigma$ = standard deviation = 0.6 years

n = sample of laptops = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the 50 randomly selected laptops will have a mean replacement time of 3.1 years or less is given by = P(M $\leq$ 3.1 years)

P(M $\leq$ 3.1 years) = P( $\frac{ M-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 3.1-3.3}{\frac{0.6}{\sqrt{50} } }} }$ ) = P(Z $\leq$ -2.357) = 1 - P(Z $\leq$ 2.357)

= 1 - 0.99078 = 0.0092 or 0.92%

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.357 in the z table which will lie between x = 2.35 and x = 2.36 which has an area of 0.99078.

Hence, the required probability is 0.0092 or 0.92%.

Now, based on the result above; Yes, the computer store has been given laptops of lower than average quality because the probability of this data is unlikely to have occurred by chance alone as the probability of happening the given event is very low as 0.92%.

8 0

3 years ago

1. (4x-3)(3x^2+8x-5)

lesya [120]

Here, you have to foil the equation.

Distribute 4x to all sides, then distribute the -3 to all sides. Next, combine like terms. If you do this, your answer will be

$12x^3+23x^2-44x+15$

6 0

4 years ago

Here are descriptions for how two dot patterns are growing,

Arisa [49]

The steps in the patterns A and B form a sequence

The attached diagram represents dots in patterns A and B

<h3>How to draw the diagrams</h3>

For pattern A, we have:

Step 2 = 10 dots

Increment of 3 dots in each step

This means that:

Step 0 = 4 dots