Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
42:35 or if simplified 6:5
Should be markdown, but if you have other options let me know and I'll tell you which it is. But if markdown is one of your choices, or if this is fill-in, it's markdown.
Answer:
34% see explanation below
Step-by-step explanation:
The total number who likes pizza is 73 and the total number of people surveyed is 215
So it'll just be 73/215 × 100 (for the percentage)
The answer would be 52.7.5