You would divide the two numbers to get 54
The length of PQ is 19.66 units
Step-by-step explanation:
The given is:
1. PK = KQ = 12
2. m∠P = 35º
We need to find the length pf PQ
∵ PK = KQ
∴ m∠P = m∠Q
∵ m∠P = 35°
∴ m∠Q = 35°
The sum of measures of the angles of a triangle is 180°
∴ m∠P + m∠Q + m∠K = 180°
∴ 35 + 35 + m∠K = 180
∴ 70 + m∠K = 180
- Subtract 70 from both sides
∴ m∠K = 110°
Let us use cosine rule to find the length of PQ
∵ PQ = 
∵ PK = 12 , KQ = 12 , m∠K = 110°
- Substitute these values in the rule
∴ PQ = 
∴ PQ = 19.66
The length of PQ is 19.66 units
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Answer:
B
Step-by-step explanation:
Using the Sine Rule in ΔABC
=
= 
∠C = 180° - (82 + 58)° = 180° - 140° = 40°
Completing values in the above formula gives
=
= 
We require a pair of ratios which contain b and 3 known quantities, that is
= 
OR
=
→ B
Answer:
1
Step-by-step explanation:
Probability = number of fruit type/total number of fruit. Total number of fruit = 5 + 9 + 5 = 19.
The probability of drawing an apple is P(apple) = number of apples/total number of fruit = 5/19.
The probability of drawing a peach is P(peach) = number of peaches/total number of fruit = 9/19
The probability of drawing an apple is P(orange) = number of oranges/total number of fruit = 5/19
The probability of drawing either an apple, peach or orange at the first draw of fruit from the bag is
P(apple or peach or orange) = P(apple) + P(peach) + P(orange)
= 5/19 + 9/19 + 5/19
= (5 + 9 + 5)/19
= 19/19
= 1
Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.