Step-by-step explanation:
from,
An = 4n -13
A1 = 4 (1) - 13
> A1 = -9
A2 = 4(2) - 13
> A2 = -5
A3 = 4(3) - 13
> A3 = -1
A4 = 4(4) - 13
> A4 = 3
The answer is CB, AC, and AB
Answer:
Error:
not 
Solution:x=0 and 3
Step-by-step explanation:
We have to find the error and correct answer
Given:![2ln x=ln(3x)-[ln9-2ln(3)]](https://tex.z-dn.net/?f=2ln%20x%3Dln%283x%29-%5Bln9-2ln%283%29%5D)
![lnx^2=ln(3x)-[ln9-ln3^2]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln3%5E2%5D)
Using the formula

![lnx^2=ln(3x)-[ln9-ln9]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln9%5D)





Therefore, x=0 and x=3
But last step in the given solution

It is wrong this property is used when
then

Hence, the student wrote
instead of
and solution is given by
x=0 and x=3
5 : -16
6 : -19
7 : -22
8 : -25
9 : -28
10: -31
11 : -34
12: -37
13: -40
14 : -43
15 : -46
16 : - 49
17 : - 52
18 : - 55
19 : - 58
20: - 61
21 : - 64
22: -67
23: -70
23rd term : is -70