Answer:
Hi there Foodalexandre! The question is good to revise knowledge on the concepts of classes and inheritance. Please find the answer with explanation below.
Explanation:
We can use a number of different object-oriented programming languages to implement this solution in, such as Java, C++, Ruby, etc. I have chosen to use Python as the language to implement because of the ease with which it can be used. First, I have defined the Vehicle class based on the description from the question, where the constructor (the __init__ method) initializes the door count and the engine sound, and the original Move() method belonging to the Vehicle class is defined. Then I define the Car class which inherits from the Vehicle class making it inherit the Vehicle properties, and initialize the Car class to have door count of 4 and engine sound as 'rrrrrr'. Defining the Move() method again in the Car class overrides the one in the Vehicle class, and the RoadTrip() method is added to return the string as requested in the question.
class Vehicle(object):
def __init__(self, door_count, engine_sound):
door_count: door_count
engine_sound: engine_sound
def Move()
:
return ‘rrrrrr’
class Car(Vehicle):
def __init__(self, door_count, engine_sound):
super().__init__(4, ‘rrrrrr’)
def Move():
return ‘vrumm’
def RoadTrip()
:
return “Not a care in the world”
Answer:
Copy and paste the needed information from text editor to clipboard then to the web browser.
Explanation:
The keylogging software is an application that can connect to the keyboard API through software APIs or could be kernel based or hypervisor based, JavaScript based etc, to capture keyboard events.
It records these events which makes this tool useful for attackers in networks. So long as the clipboard logging or screen logging does not accompany the keyboard loggers, data can be copied on clipboard and pasted to the target point.
Explanation:
Explanation:
RSA encryption is performed by calculating C=M^e(mod n).
However, if n is much larger than e (as is the case here), and if the message is not too long (i.e. small M), then M^e(mod n) == M^e and therefore M can be found by calculating the e-th root of C.
Arpanet. I think is the answer.
