Answer:
Answered below
Explanation:
//Program is written in Java programming //language
Class Box{
private double length;
private double width;
private double height;
Box(double len, double wid, double hgt){
length = len;
width = wid;
height = hgt;
}
public double volumeOfBox( ){
double volume = length * width * height;
return volume;
}
public double getLength( ){
return length;
}
public double getWidth( ){
return width;
}
public double getHeight( ){
return height;
}
}
Reject Code 0503<span> indicates that the Spouse's Social Security Number and the first 4 letters of the spouse's last name </span>do<span> not match IRS records. The IRS uses data provided by the Social Security Administration to verify this information. Hope this helps.</span>
Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.
The body part that is close to the arc flash boundary is the energized conductors or circuit parts.
<h3>What is the distance of an arc flash?</h3>
The working distance is known to be the distance that exist between a person and the center of an arc flash.
Note that The body part that is close to the arc flash boundary is the energized conductors or circuit parts.
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