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sergejj [24]
2 years ago
5

Find the value of each expression. 30 ÷ 3 × 2

Mathematics
2 answers:
irina [24]2 years ago
8 0

Answer:

20

Step-by-step explanation:

30 ÷ 3 × 2

(Since it’s division and multi platoon, we just go left to right)

10 × 2

20

Agata [3.3K]2 years ago
7 0

Answer:

Step-by-step explanation:

1) First division has to be done.

2) After that multiplication has to be done.

30 ÷ 3 * 2 = 10 * 2

                 = 20

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Let f(x) = -3x + 2 and g(x) - 4x + 6. Find (f•g)(-5).
mezya [45]

Answer:

(f•g)(-5) = -238

Step-by-step explanation:

We have that:

f(x) = -3x + 2

g(x) = 4x + 6

Find (f•g)(-5).

First we find (f.g)(x)

So

f(x)*g(x) = (-3x + 2)*(4x + 6) = -12x² -10x + 12

When x = -5

-12(-5)² - 10(-5) + 12 = -238

(f•g)(-5) = -238

6 0
3 years ago
Round 637.892 to whole number
Stels [109]

Answer:

638

Step-by-step explanation:

its 638, not 639 because its above 638.5

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3 years ago
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babunello [35]

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5 0
2 years ago
Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

  {1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

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Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.

It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

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Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

  a=1, b=1, c=-4

  x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2

  x = (-1 ±√17)2

The zeros are 1 and (-1±√17)/2.

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The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

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The given expression factors as ...

  4(x -1)(x² +x -4)

5 0
3 years ago
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Use the equation P(A or B)= P(B)-P(A and B) to find the missing value below.
Anvisha [2.4K]

Answer:

P(B) = \frac{7}{8}

Step-by-step explanation:

Given

P(A or B)= P(B)-P(A and B)

P(A)=1/3

P(A and B)=1/8

P(A or B)= 3/4

Required

Find P(B)

To find P(B), all we need to do is to substitute values of P(A or B) and P(A and B) in the given equation.

This goes thus;

P(A or B) = P(B) - P(A and B) becomes

\frac{3}{4} = P(B) - \frac{1}{8}

Make P(B) the subject of formula

P(B) = \frac{3}{4} + \frac{1}{8}

Take L.C.M

P(B) = \frac{6 + 1}{8}

Add fractions

P(B) = \frac{7}{8}

From the workings above, the value of P(B) using the given equation is \frac{7}{8}

6 0
3 years ago
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