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ira [324]
3 years ago
8

How do you graph y= 3x-2

Mathematics
2 answers:
larisa86 [58]3 years ago
5 0

Answer:

Plug in x values into the equation. Start by making a table with x on one side and y on the other. Then, plug in an x value into the equation. We'll start by plugging in 0. This would give us y=3(0)-2, which simplifies to y=-2. Now we know that when x=0, y=-2, so write these two values in your table. Next, we can do this with more points. Let's plug in 1 for x. This gives us y=3(1)-2, which simplifies to y=1 when x=1. Again, we'll write this in our table. After we have a few pairs of x and y values, then we'll draw these points on the graph.

Step-by-step explanation:

stepladder [879]3 years ago
3 0

Step-by-step explanation:

start at -2 on the y axis and go up 1 to the right 3 and so on

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Helppppp i dont get it and its due tonighttt pleaseeeee
Ghella [55]

Answer:

Lol have fun

Step-by-step explanation:

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3 years ago
A local university accepted 2300 students out of 4500 applicants for admission. What was the acceptance rate expressed as a perc
mario62 [17]
(2300 / 4500) * 100 = 51.1%

Hope this helps! :)
5 0
4 years ago
PLEASE HELP ASAP! I don’t recall how to do this!
MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

(1.05)^x=1.885

In order to solve for x, we have to get it out from its position of an exponent.  Do that by taking the natural log of both sides:

ln(1.05)^x=ln(1.885)

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

x=\frac{ln(1.885)}{ln(1.05)}

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

ln(x*x^2)=5

Simplifying gives you

ln(x^3)=5

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

ln(x)=\frac{5}{3}

Take the inverse ln by raising each side to e:

e^{ln(x)}=e^{\frac{5}{3}}

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

\frac{1}{2}=e^{.1x}

"Undo" that e by taking the ln of both sides:

ln(.5)=ln(e^{.1x})

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others.  Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

(2^2)^x-6(2)^x=-8

Now we will bring over the -8 by adding:

(2^2)^x-6(2)^x+8=0

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution.  Let's let u=2^x

When we do that, we can rewrite the polynomial as

u^2-6u+8=0

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor.  Now we have to put it back in:

2^x=4,2^x=2

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

2^2=2^x

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

2^x=2^1

Now that the bases are the same, we can say that

x = 1

5 0
3 years ago
Find m∠QPR..........
dexar [7]

Hey there! :)

Answer:

m∠QPR = 25°.

Step-by-step explanation:

Given:

m∠QPS = 40°

m∠RPS = 8x + 7°

m∠QPR = 9x + 16°

m∠QPS = m∠RPS + m∠QPR, therefore:

40° = 8x + 7° + 9x + 16°

Combine like terms:

40° = 17x + 23°

Subtract 23° from both sides:

17° = 17x°

Divide both sides by 17:

x = 1°

If m∠QPR = 9x + 16°, substitute in 1 for 'x':

9(1) + 16 = 9 + 16 = 25°.

3 0
3 years ago
Read 2 more answers
What has mechanical energy? Choose more than one answer.
S_A_V [24]

Step-by-step explanation:

a battery

b windmill

e river

f helicopter

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4 years ago
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