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2 years ago

How do you graph y= 3x-2

Mathematics

2 answers:

larisa86 [58]2 years ago

5 0

Answer:

Plug in x values into the equation. Start by making a table with x on one side and y on the other. Then, plug in an x value into the equation. We'll start by plugging in 0. This would give us y=3(0)-2, which simplifies to y=-2. Now we know that when x=0, y=-2, so write these two values in your table. Next, we can do this with more points. Let's plug in 1 for x. This gives us y=3(1)-2, which simplifies to y=1 when x=1. Again, we'll write this in our table. After we have a few pairs of x and y values, then we'll draw these points on the graph.

Step-by-step explanation:

stepladder [879]2 years ago

3 0

Step-by-step explanation:

start at -2 on the y axis and go up 1 to the right 3 and so on

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7/9 - 2/3 and 2/3 - 1/6 <br>

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Answer:

The answer is 1/9 and 1/2

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Need Answer Fast). The solution to a problem is an irrational number. which statement is true about the solution? Will Mark Bra

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Step-by-step explanation:

There is no option to choose from, but the knowledge of what irrational numbers are, would help cover this cost.

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If a number cannot be written as a simple fraction, then it is called irrational.

Example of irrational numbers: √2, π

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2 years ago

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The table shows the relationship between the number of Calories Lucie burns while jumping rope and the number of minutes she jum

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Answer:

The amount of calories Lucie will burn by jumping for 1 minute is 8 calories

Step-by-step explanation:

The given data values are;

Minutes ${}$ Calories Burned

40 ${}$ 320

80 ${}$ 640

120 ${}$ 960

160 ${}$ 1280

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40 minutes of jump rope will yield 320 calories burnt

Therefore we have;

1 minute of jump rope will yield 320/40 = 8 calories burnt

The amount of calories Lucie will burn by jumping for 1 minute = 8 calories.

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3 years ago

Richard has just been given an l0-question multiple-choice quiz in his history class. Each question has five answers, of which o

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Answer:

a) 0.0000001024 probability that he will answer all questions correctly.

b) 0.1074 = 10.74% probability that he will answer all questions incorrectly

c) 0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

d) 0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of any other question. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Each question has five answers, of which only one is correct

This means that the probability of correctly answering a question guessing is $p = \frac{1}{5} = 0.2$

10 questions.

This means that $n = 10$

A) What is the probability that he will answer all questions correctly?

This is $P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} = 0.0000001024$

0.0000001024 probability that he will answer all questions correctly.

B) What is the probability that he will answer all questions incorrectly?

None correctly, so $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074$

0.1074 = 10.74% probability that he will answer all questions incorrectly

C) What is the probability that he will answer at least one of the questions correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

Since $P(X = 0) = 0.1074$ , from item b.

$P(X \geq 1) = 1 - 0.1074 = 0.8926$

0.8926 = 89.26% probability that he will answer at least one of the questions correctly.

D) What is the probability that Richard will answer at least half the questions correctly?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{10,5}.(0.2)^{5}.(0.8)^{5} = 0.0264$

$P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055$

$P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008$

$P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001$

$P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0$

$P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0$

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0264 + 0.0055 + 0.0008 + 0.0001 + 0 + 0 = 0.0328$

0.0328 = 3.28% probability that Richard will answer at least half the questions correctly

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3 years ago

The student council sells cookies every 9 days and ice cream every 12 days. If both are being sold today, how many days will it

blondinia [14]

Cookies : 9, 18, 27, 36,
Ice cream: 12, 24, 36

So in 36 days.

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3 years ago

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