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Norma-Jean [14]
3 years ago
5

Round 614,594 to the nearest ten thousand?

Mathematics
1 answer:
MrMuchimi3 years ago
7 0

Answer:

610,000

Step-by-step explanation:

14,000 would be the nearest ten thousandth but its is not over 15,000 so it would round down to 10,000 making the answer 610,000.

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if grace and claire parents each invested 7,600 into college saving account when the girls were born how much money will each gi
Mrrafil [7]

Answer:

7,600

Step-by-step explanation:

both parents invest 7,600.

7,600x2= 15,200

there are 2 girls so divide 15,200 by 2 and u get 7,600

3 0
2 years ago
Plz helpppppp me with this question​
jarptica [38.1K]

Answer:

R L Q

Step-by-step explanation:

Im pretty sure thats right sorry if Its not

4 0
3 years ago
Read 2 more answers
2950 - 125 - 50 =<br> I dont resly understand
Masja [62]

Answer:

2950 - 125 - 50 \\ =  2950 - (125 + 50) \\  = 2950 - 175 \\  =  \boxed{2775}

<h3><u>2775</u> is the right answer.</h3>
7 0
3 years ago
The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 i
stich3 [128]

Complete question :

The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 inches. Round answers to the nearest tenth of a percent. a) What percentage of years will have an annual rainfall of less than 43 inches? b) What percentage of years will have an annual rainfall of more than 39 inches? c) What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

Answer:

0.61053

0.66314

0.26647

Step-by-step explanation:

Given that :

Mean (m) = 41.4 inches

Standard deviation (s) = 5.7 inches

a) What percentage of years will have an annual rainfall of less than 43 inches?

P(x < 43)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (43 - 41.4) / 5.7 = 0.2807017

p(Z < 0.2807) = 0.61053 ( Z probability calculator)

b) What percentage of years will have an annual rainfall of more than 39 inches? c)

P(x > 39)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (39 - 41.4) / 5.7 = −0.421052

p(Z > −0.421052) = 0.66314 ( Z probability calculator)

What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

P(x < 38)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (38 - 41.4) / 5.7 = −0.596491

p(Z < −0.596491) = 0.27545 ( Z probability calculator)

P(x < 42)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (42 - 41.4) / 5.7 = 0.1052631

p(Z < 0.1052631) = 0.54192 ( Z probability calculator)

0.54192 - 0.27545 = 0.26647

6 0
3 years ago
At the Battle of Breed’s Hill about 1,600 Americans fought against 2,400 British Troops. If the British suffered 44% of the casu
NeX [460]
2400 divided by 44% which is 1056.





(sneaky way to put history in math, btw...)
4 0
3 years ago
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