Can someone help please???
1 answer:
Answer:
Step-by-step explanation:
<u><em>AAS theorem: </em></u><em>If two angles and a non-included side of one triangle are congruent to corresponding two angles and a non-included side of second triangle, then the triangles are congruent.</em>
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1). ∠N ≅ ∠L Given
2). JK ≅ MK Given
3). ∠JKN ≅ ∠MKL Vertical
4). ΔJKN ≅ ΔMKL AAS theorem of congruence.
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1. The terms of a sequence are denoted by 
2.
3. so it is clear that the first columns add each time by one, and the second column add by 2, then by 4, by 6, by 8 and so on.
4. consider only the second column and how we get the terms, which we will call
:
5.
So
![u_{n}=(n+1)(1+2{1+2+3+....(n-1)}) =(n+1)(1+2 [(n-1)n/2]) = (n+1)(1+(n-1)n) =(n+1)( n^{2}-n+1 ) ](https://tex.z-dn.net/?f=u_%7Bn%7D%3D%28n%2B1%29%281%2B2%7B1%2B2%2B3%2B....%28n-1%29%7D%29%0A%20%20%20%20%20%20%20%20%0A%20%20%20%20%20%20%20%20%20%3D%28n%2B1%29%281%2B2%20%5B%28n-1%29n%2F2%5D%29%0A%0A%20%20%20%20%20%20%20%20%20%3D%20%28n%2B1%29%281%2B%28n-1%29n%29%0A%20%20%20%20%20%20%20%0A%20%20%20%20%20%20%20%20%20%3D%28n%2B1%29%28%20n%5E%7B2%7D-n%2B1%20%29%0A%20%20%20%20%20%20%20%20%20)
6. We can check:
7. Remark: Gauss addition formula: 1+2+3+....+n=n(n+1)/2
2.
3. so it is clear that the first columns add each time by one, and the second column add by 2, then by 4, by 6, by 8 and so on.
4. consider only the second column and how we get the terms, which we will call
5.
So
6. We can check:
7. Remark: Gauss addition formula: 1+2+3+....+n=n(n+1)/2