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weeeeeb [17]
3 years ago
6

How to solve this equation

Mathematics
1 answer:
kirill [66]3 years ago
8 0

a = 20
a/5 + 6 = 10

Subtract 6 from both sides:
a/5 = 4

multiply both sides by 5:
a = 20
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Marylee paid $40 for an item after she received a 20% discount. Marylee's friend says this means that the original price of the
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Step-by-step explanation:

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2 years ago
If 3220 = 80+7, what is the value of c?
Setler79 [48]

Answer:

Correct option is

C

36.25

Modal class =30−40

So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒  Mode=l+2f1−f0f2f1−f0×h

                  =30+2×32−12−2032−12×10

                  =30+6.25

                  =36.25

∴  Mode =36.25

8 0
3 years ago
10x + 1 = 2(3× + 5) - 1
MArishka [77]

Answer:

x = 2

Step-by-step explanation:

10x + 1 = 2(3x + 5) - 1

  1. mutlipy the 2 to the 3x and the 5
  2. you should get 10x + 1 = 6x + 10 - 1
  3. now you have to add the combine terms
  4. so it will now be 10x + 1 = 6x + 9
  5. now you.have to get the x's on one side and the constants (numbers alone) on the other side
  6. so you can subtract the 6x on both sides
  7. once you do that you wil get 4x + 1 = 9
  8. After you get this equation you will have to subtract the one from both sides.
  9. you will get 4x = 8
  10. All you have to do it divide 4 on both sides. Your final answer is x = 2.
7 0
3 years ago
Read 2 more answers
What is the m GE bisects Find m
nirvana33 [79]

Answer:

DGF = 106

Step-by-step explanation:

Bisects means to divide in half, with two equal parts

DGF = DGE + EGF

DGE = EGF

DGF = DGE + DGE

DGF = 53+53

DGF = 106

8 0
3 years ago
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The coordinates of the vertices of ΔPQR are (–2, –2), (–6, –2), and (–6, –5).
melamori03 [73]
<h3>Answer:</h3>

Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis

<h3>Explanation:</h3>

The problem statement tells you the transformation is ...

... (x, y) → (x, -y)

Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.

Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)

An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.

So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.

6 0
3 years ago
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