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liq [111]
3 years ago
8

Find a polynomial equation that has zeros at x = -2, x = 0, x = 3 and x = 5

Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer: its B

Step-by-step explanation:

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Given a normal distribution with a mean of 128 and a standard deviation of 15, what percentage of values is within the interval
tatyana61 [14]

Answer:

E. 99.7%

Step-by-step explanation:

Calculate each z-score.

z = (x − μ) / σ

z = (173 − 128) / 15

z = 3

z = (x − μ) / σ

z = (83 − 128) / 15

z = -3

You can use a z-score table, or use the empirical rule.

P(-3 < z < 3) = 99.7%.

6 0
3 years ago
Is the ratio 4 to 7 the same as 7 to 4 ?
Olin [163]

Answer:

uhhhhh Expressed as a fraction, with the numerator equal to the first quantity and the denominator equal to the second, the answer would be 7/4. Two other ways of writing the ratio are 7 to 4, and 7:4.

Step-by-step explanation:

just math

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=-0.2%5Csqrt%7Bx%5E2%7D" id="TexFormula1" title="-0.2\sqrt{x^2}" alt="-0.2\sqrt{x^2}" align="ab
madreJ [45]

Answer:

The simplified answer to that is -0.2x.

Hope this helps and if you could mark this as brainliest. Thanks!

6 0
3 years ago
Read 2 more answers
Find the area of a trapezoid if the altitude is 6 inches and the median is 8 inches. (Hint: Recall that the median of a
zlopas [31]

Answer:

48 sq. units

Step-by-step explanation:

The area of a trapezoid is given by half sum of the bases multiplied by the height

=\frac{1}{2} (a+b)h

where a and b are the two parallel sides of the trapezoid and h is the height or amplitude of the trapezoid

But you are aware that, the median of a trapezoid is equal to half the sum of the bases, thus the first part of the formulae  is covered by the median

Median=\frac{1}{2} (a+b)

Hence area, A, of a trapezoid is simplified to product of median and amplitude

A=amplitude*median\\\\A=6*8=48sq.units

3 0
4 years ago
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PlS HeLP!!!<br> what number makes this equation true?<br> _ ÷8=4
Lunna [17]
32 is the right answer
5 0
3 years ago
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