.85 repeating as a fraction is
A 99-inch board is cut into two pieces. One piece is two times the length of the other. Find the length of the shorter piece.
2 answers:
Answer:
33 inches
Step-by-step explanation:
The question above can be solved by using<em> "algebraic expressions." </em>
Let x be the length of the <em>shorter piece.</em>
Let 2x be the length of the<em> longer piece.</em>
Let's solve.
- x + 2x = 99 (inches)
- 3x = 99
- x =
- x = 33
The length of the shorter piece is 33 inches.
Let's get the length of the longer piece.
- 2x = ?
- 2(33) = 66
The length of the longer piece is 66 inches.
Let's check.
x + 2x = 99 inches
33 + 66 = 99
99 = 99
The answer is correct.
You might be interested in
Answer:
Step-by-step explanation:
So the first step is to add like terms since you can simplify the numerator by adding the two values sine they have the same variable and degree.
Add like terms:
Divide by 2x (divide coefficient by 2, subtract coefficient degrees)
Multiply exponents and raise 4 to the power of 5
The reason you multiply exponents is because you can think about it like this:
(4 * x * x * x * x * x * x * x * x) (this has one 4 and 8 x's because x is raised to the power of 8. Now if you do that 5 times which is what the exponent is doing you're going to have 40 x's and 8 4's. So it's essentially
(4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x) * (4 * x * x * x * x * x * x * x * x). If you group like terms you'll get (4 * 4 * 4 * 4 * 4) * (x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x * x). Which simplifies to 4^5 * x ^ (8 * 5) which further simplifies to the answer 1024x^40
The lowest common denominator is lcm(5, 3), which is 15.
The sum of 2/5 + 5/3 + 9/3 is 6/15 + 25/15 + 45/15, which is 76/15 or .
<em>⇨ Use the formula below</em>
<em />
<em>⇨ Substitute the parameters:</em>
<em />
<em />
Hope that helped