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lana66690 [7]
3 years ago
8

if 10 ml of acetone (60) is diluted with water to a total solution volume of 200 ml, what is the percent by volume of acetone in

the solution?
Chemistry
1 answer:
sergey [27]3 years ago
6 0

Answer:

5%

Explanation:

Given parameters:

Volume of original acetone before dilution = 10ml

Volume of diluted solution = 200ml

Unknown:

Percent volume of acetone in the solution = ?

Solution:

To find the percent volume of acetone in the diluted solution, use the expression below;

 Percent volume of acetone = \frac{volume of original acetone}{diluted volume}  x 100

Insert the parameters and solve;

 Percent volume of acetone  = \frac{10}{200}  x 100 = 5%

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Elanso [62]
V=84.0 mL = 84.0 cm³
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3 years ago
A compound is composed of 85.6% Carbon and the rest is Hydrogen. The molecular mass of the compound is 42.078g/mol. What is the
s344n2d4d5 [400]

The molecular formula for the compound is  C_{3} H_{6}

<u>Explanation</u>:

As with all of these problems, we assume 100 g of an unknown compound.

And thus, we determine the elemental composition by the given percentages.

Moles of carbon = 85.64 / 12.011

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Moles of hydrogen = 14.36 / 1.00794

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There are 2 moles of hydrogen per mole of carbon. And thus the empirical formula is CH_{2}.

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Thus, 42.08 = n × (12.011 + 2 × 1.00794)

And thus n = 3, and molecular formula = C_{3} H_{6}

3 0
3 years ago
A sample of air at 58.6 kPa is expanded from 250 mL to 655 mL. If thetemperature remains constant, what is the final pressure in
kati45 [8]

Answer:

<h2>22.366 kPa</h2>

Explanation:

The final pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question

58.6 kPa = 58600 Pa

We have

P_2 =  \frac{58600 \times 250}{655}  =  \frac{14650000}{655}  \\  = 22366.4122... \\  = 22366

We have the final answer as

<h3>22.366 kPa</h3>

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3 years ago
How many N2 molecules would exist in 500g of water at 20C?
tankabanditka [31]

We have to know the number of molecules present in 500 g of water.

The answer is: zero molecules present in 500g of water.

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There is no existence of N₂ molecule.

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