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sergejj [24]
2 years ago
9

14 points! (The graph is at the right corner)

Mathematics
1 answer:
makkiz [27]2 years ago
8 0

Answer: big dad nipples with a big boom boom as

Step-by-step explanation:

ez bro

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U=15+2as find the value of S​
Vinvika [58]

Start with

u=15+2as

Subtract 15 from both sides:

u-15=2as

Divide both sides by 2a:

\dfrac{u-15}{2a}=s

7 0
3 years ago
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Clem Shirestock is at a dock on a bank of a straight river that is 1 mile wide and wants toreach the barge toll gate on the othe
oee [108]

The total time taken by Clem Shirestock to reach the gate is given by the  equation 7 = 4√(x²+1)+ 8 - 2 x

Let the point P is at a distance of x miles from the toll gate.

Hence when Clem reaches the point P he rows in the form of right angled triangle. and we know that the width of the river is 1 mile.

So by using Pythagoras Theorem we can infer that the distance covered by Clem is the hypotenuse which is equal to √(x²+1).

Time taken to complete this route is  4√(x²+1) .

Now  he has only to walk 4-x distance along the river.

His speed is 2 mph

Time taken = 2(4-x) = 8-2x

Hence we can conclude that the total time is 7 hours. so the equation to represent this is 7 = 4√(x²+1)+ 8 - 2 x .

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3 0
1 year ago
A particle in the first quadrant is moving along a path described by the equation LaTeX: x^2+xy+2y^2=16x 2 + x y + 2 y 2 = 16 su
ElenaW [278]

Answer:

\frac{50}{3} cm/sec.

Step-by-step explanation:

We have been given that a particle in the first quadrant is moving along a path described by the equation x^2+xy+2y^2=16 such that at the moment its x-coordinate is 2, its y-coordinate is decreasing at a rate of 10 cm/sec. We are asked to find the rate at which x-coordinate is changing at that time.

First of all, we will find the y value, when x =2 by substituting x =2 in our given equation.

2^2+2y+2y^2=16

4-16+2y+2y^2=16-16

2y^2+2y-12=0

y^2+y-6=0

y^2+3y-2y-6=0  

(y+3)(y-2)=0

(y+3)=0,(y-2)=0

y=-3,y=2

Since the particle is moving in the 1st quadrant, so the value of y will be positive that is y=2.

Now, we will find the derivative of our given equation.

2x\cdot x'+x'y+xy'+4y\cdot y'=0

We have been given that y=2, x =2 and y'=-10.

2(2)\cdot x'+(2)x'+2(-10)+4(2)\cdot (-10)=0

4\cdot x'+2x'-20-80=0

6x'-100=0

6x'-100+100=0+100

6x'=100

\frac{6x'}{6}=\frac{100}{6}

x'=\frac{50}{3}

Therefore, the x-coordinate is increasing at a rate of \frac{50}{3} cm/sec.

7 0
3 years ago
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Help!! need to find the area
stiks02 [169]

Answer:

10*5 +2(2*2)

50+8

58

Step-by-step explanation:

3 0
3 years ago
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