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Alona [7]
4 years ago
14

Jordan has 10 friends in the school band. The number of his friends who play the saxophone is shown in the grid. Use the grid to

complete the statements and help Jordan find the percent of his band friends who play the saxophone.
A bar diagram has 3 shaded squares and 7 unshaded squares.

The grid has
total squares.
Jordan needs
copies of the grid to have 100 total squares.
With that many copies of the grid, the 3 shaded squares will become
.
So,
of Jordan’s band friends play the saxophone.

Mathematics
2 answers:
slava [35]4 years ago
7 0
Jordan needs 10 copies of the squares to have 100
With that, there will be 30 shades squares
So 30% of Jordan’s friends play sax
pychu [463]4 years ago
4 0

Answer:

1st - 10 2nd -10 3rd - 30 4th -30

Step-by-step explanation:

Jordan has 10 friends in the school band. The number of his friends who play the saxophone is shown in the grid. Use the grid to complete the statements and help Jordan find the percent of his band friends who play the saxophone.

A bar diagram has 3 shaded squares and 7 unshaded squares.

The grid has

✔ 10

total squares.

Jordan needs

✔ 10

copies of the grid to have 100 total squares.

With that many copies of the grid, the 3 shaded squares will become

✔ 30

.

So,

✔ 30%

of Jordan’s band friends play the saxophone.

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4 0
3 years ago
A package of 3 pairs of insulated gloves costs $15.57. What is the unit price of the pairs of gloves?
Illusion [34]

Answer:

$5.19

Step-by-step explanation:

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3 : 15.57

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1 : 5.19

8 0
3 years ago
Can you guyz help me with this question step by step please ☺️
zlopas [31]
2 1/2 x 3 = 7 1/2 = 7 4/8

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A is the correct answer

7 0
3 years ago
Suppose that only 20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe
Lina20 [59]

Answer:

a) 91.33% probability that at most 6 will come to a complete stop

b) 10.91% probability that exactly 6 will come to a complete stop.

c) 19.58% probability that at least 6 will come to a complete stop

d) 4 of the next 20 drivers do you expect to come to a complete stop

Step-by-step explanation:

For each driver, there are only two possible outcomes. Either they will come to a complete stop, or they will not. The probability of a driver coming to a complete stop is independent of other drivers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

This means that p = 0.2

20 drivers

This means that n = 20

a. at most 6 will come to a complete stop?

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.2)^{0}.(0.8)^{20} = 0.0115

P(X = 1) = C_{20,1}.(0.2)^{1}.(0.8)^{19} = 0.0576

P(X = 2) = C_{20,2}.(0.2)^{2}.(0.8)^{18} = 0.1369

P(X = 3) = C_{20,3}.(0.2)^{3}.(0.8)^{17} = 0.2054

P(X = 4) = C_{20,4}.(0.2)^{4}.(0.8)^{16} = 0.2182

P(X = 5) = C_{20,5}.(0.2)^{5}.(0.8)^{15} = 0.1746

P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 + 0.1091 = 0.9133

91.33% probability that at most 6 will come to a complete stop

b. Exactly 6 will come to a complete stop?

P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091

10.91% probability that exactly 6 will come to a complete stop.

c. At least 6 will come to a complete stop?

Either less than 6 will come to a complete stop, or at least 6 will. The sum of the probabilities of these events is decimal 1. So

P(X < 6) + P(X \geq 6) = 1

We want P(X \geq 6). So

P(X \geq 6) = 1 - P(X < 6)

In which

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 = 0.8042

P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8042 = 0.1958

19.58% probability that at least 6 will come to a complete stop

d. How many of the next 20 drivers do you expect to come to a complete stop?

The expected value of the binomial distribution is

E(X) = np = 20*0.2 = 4

4 of the next 20 drivers do you expect to come to a complete stop

4 0
4 years ago
- ignore this :)<br><br> thank you v much.
yan [13]

Answer:

i dont know what you mean by ignore this and it looks like you got it

Step-by-step explanation:

8 0
3 years ago
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