<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
<span>Equation F can be written as 2d + 1 = 3d + 7.</span>
Step-by-step explanation:
logx√2=1/6
<=> logx(2^1/2)=1/6
<=>1/2.logx(2)=1/6
<=>logx(2)=1/3
<=>2=x^1/3
<=>x=
Sorry I forgot the formula in the last step
I = PRT
P = 8000
T = 4
R = 12%...turn to decimal...0.12
now we sub
I = (8000)(0.12)(4)
I = 3840 <==
