Evaluate the expression for d = 3. 2(d +8)= ??
2 answers:
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9514 1404 393
Answer:
- see below for a sketch
- 12 km
Step-by-step explanation:
The distance can be calculated using the Law of Cosines. The angle internal to the triangle at Q is (180°-(146° -65°)) = 99°. Then the distance PR can be found from ...
PR² = PQ² +QR² -2·PQ·QR·cos(∠PQR)
PR² = 6² +10² -2·6·10·cos(99°) ≈ 154.77
PR ≈ √154.77 ≈ 12.44 . . . . km
The distance PR is about 12 km.
Answer:
is the required polynomial with degree 3 and p ( 7 ) = 0
Step-by-step explanation:
Given:
p ( 7 ) = 0
To Find:
p ( x ) = ?
Solution:
Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.
Therefore zero's of the polynomial is seven i.e 7
Degree : Highest raise to power in the polynomial is the degree of the polynomial
We have the identity,
Take a = x
b = 7
Substitute in the identity we get
Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.
p ( 7 ) = 7³ - 21×7² + 147×7 - 7³
p ( 7 ) = 0