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3 years ago

All parallelograms are _____

Mathematics

2 answers:

Natali5045456 [20]3 years ago

8 0

Answer:

All parallelograms are squares.

Step-by-step explanation:

jekas [21]3 years ago

8 0

All parallelograms are quadrilaterals

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What the answer is I don't get it

NISA [10]

The answer is 1/2 because 1 = 2/2 3/2 minus 2/2 = 1/2

6 0

3 years ago

Read 2 more answers

4 Consider the triangle below.

Maurinko [17]

<h2>=>> <u>Solution (part A</u>) :</h2>

Given :

▪︎Triangle AMG is an isosceles triangle.

▪︎Measure of segment AM = (x+1.4) inches

▪︎Measure of segment MG = (2x+0.1) inches

▪︎Measure of segment AG = (3x-0.4) inches

▪︎segment AG is the base of triangle AMG.

Since AG is the base of the isosceles triangle AMG, segment AM and segment MG will be equal.

Which means :

$= \tt x + 1.4 = 2x + 0.1$

$= \tt x + 1.4 - 0.1 = 2x$

$= \tt \: x + 1.3 = 2x$

$= \tt 1.3 = 2x - x$

$\color{plum} \hookrightarrow \tt x = 1.3$

Thus, the value of x = 1.3

Therefore :

▪︎The value of x = 1.3

<h2>=>> <u>Solution (Part B)</u> :</h2>

We know that :

▪︎The value of x = 1.3

Which means :

The length of the leg AM :

$= \tt x + 1.4$

$= \tt 1.3 + 1.4$

$\color{plum} \tt leg \: AM= 2.7 \: inches$

Thus, the length of the leg AM = 2.7 inches

The length of leg MG :

$= \tt 2x + 0.1$

$= \tt2 \times 1.3 + 0.1$

$= \tt 2.6 + 0.1$

$\color{plum} \tt\: leg \:MG = 2.7 \: inches$

Thus, the length of the leg MG = 2.7 inches

Since the measure of the two legs are equal (2.7=2.7), we can conclude that we have found out the correct length of each leg.

Therefore :

▪︎Measure of leg AM = 2.7 inches

▪︎Measure of leg MG = 2.7 inches

<h2>=>> <u>Solution </u><u>(</u><u>part C</u><u>)</u> :</h2>

We know that :

Value of x = 1.3

Then, measure of the base AG :

$= \tt 3x - 0.4$

$= \tt 3 \times 1.3 - 0.4$

$= \tt 3.9 - 0.4$

$\color{plum}\tt \: Base \: AG = 3.5 \: inches$

Thus, the measure of the base = 3.5 inches

Therefore :

▪︎ the length of base AG = 3.5 inches.

6 0

3 years ago

The 10 students who completed a special flying course are waiting to see if they will be awarded the one Distinction or the one

yaroslaw [1]

Answer: 1)100ways and 2)90ways

Step-by-step explanation:

Given :-The 10 students who completed a special flying course are waiting to see if they will be awarded the one Distinction or the one Merit award for their efforts.

Ways can the two awards be given if the same student can receive both awards (i.e repetition is allowed)

=10×10=100ways

Ways can the two awards be given if the same student cannot receive both awards(i.e. repetition is not allowed)

=10×9=90ways

3 0

3 years ago

Twenty-one boys and eight girls go on a camping trip. In how many ways can a group of six be selected to gather firewood, given

lorasvet [3.4K]

(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys

Required number of ways for 2g / 4b = 28 * 5985 = 167,580

(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.

2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28

adding these up we get the answer to (b) which is 257,964

6 0

3 years ago

Greatest common factor for 17 and 42

Musya8 [376]

Since 17 isnt a factor of 42 the only factor is 1

5 0

3 years ago