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Misha Larkins [42]
2 years ago
14

2. cos 0° a) sin 1° b) c) sin 90° d) tan 90° B)cos 1°

Mathematics
1 answer:
motikmotik2 years ago
5 0

Answer:

sin 90

Step-by-step explanation:

cos (0)

Using the unit circle, we know that cos 0=1

sin 1 and cos 1  are not equal to 1

sin 90 =1

tan 90 = sin 90/ cos 90 = 1/0 =undefined

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can some one also please help my one that i should do after i finds the area of the square aka how to find the area of the trian
Andre45 [30]

Answer:

6 square units

Step-by-step explanation:

Given shape is of a trapezoid:

area \: of \: trapezoid  \\ =  \frac{1}{2}  \times (4 + 2) \times 2 \\  \\  = 6 \:  {units}^{2}

Area of shape = area of square + area of triangle

= 2^2 + \frac{1}{2} \times 2\times 2\\= 4 + 2\\= 6\: units^2 \\

4 0
3 years ago
Find the sum. 2/5 + 1/2​
dybincka [34]
2/5 + 1/2

4+5 / 10 • look for the LCD of 5 and 2
which is 10 then 5 goes 2
times into 10 the multiply by 2
= 4. Then 2 goes 5 times into
10 then multiply by 1 = 5.

Therefore the sum of 2/5 + 1/2 =9/10
5 0
3 years ago
Read 2 more answers
4 +y = 12. Substitute 8 for x.
Alexeev081 [22]

Answer:

where should I substitute 8 for x? if its like this 4(8)+y=12 than its y=-20

Step-by-step explanation:

8 0
3 years ago
Gabe spends 25% of class talking. If class is 90 minutes how many minutes did he spend talking?
Gekata [30.6K]
He spent 27.7 repeating minutes of his class talking.
8 0
3 years ago
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Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask
Kay [80]

Answer:

Let X be the event of feeling secure after saving $50,000,

Given,

The probability of feeling secure after saving $50,000, p = 40 % = 0.4,

So, the probability of not  feeling secure after saving $50,000, q = 1 - p = 0.6,

Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

That is, n = 8

(a) the probability of the number that say they would feel secure is exactly 5

P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

=0.12386304

(b) the probability of the number that say they would feel secure is more than five

P(X>5) = P(X=6)+ P(X=7) + P(X=8)

=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}

=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8

=0.04980736

(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3

=0.95019264

8 0
3 years ago
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