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Naily [24]
3 years ago
6

A father uses a rope to pull a child on a sled at a constant speed. of the ones listed which forces are present?

Physics
1 answer:
Amanda [17]3 years ago
4 0

All the forces may be present.

The child on the sled has a weight- which is due to the force of gravity on the child and the sled.

The sled and the child exert a force on the ground equal to the combined weight of the sled and the child. The ground exerts a normal force on the sled.

The force used by the father to pull the sled is the applied force.

The sled slides on the ground and as a result, the force of friction exists between the ground and the sled, directed opposite to the direction of the motion of the sled.

The father pulls the sled using a rope. As a result, the rope is under Tension.

As the sled moves it also experiences a force of air resistance, which is dependent on the sled's speed.

However, since the father pulls the sled along with constant speed, the sum of all the forces acting on the sled is zero.

Since there is no movement in the upward or downward directions, the weight of the child and the sled is equal to the normal force acted upon the sled by the ground.

The force applied by the father on the rope is equal to the tension in the rope.

Friction and air resistance act opposite to the direction of motion of the sled. for the sled to move at constant speed, the tension in the rope must be equal to the sum of the forces due to friction and air resistance.

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Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

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speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

K.E_{max} = P.E_{max}

K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J

Thus, P.E_{max} = 109,375 \ J

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3 0
2 years ago
Acceleration increases over time once a force is applied to the object. Given a force of 10.0 Newtons, which mass will have the
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Mass is indirectly proportional to acceleration, so, lighter the object greater would be it's acceleration...

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3 years ago
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By how much does the volume of an aluminum cube 4.00 cm on an edge increase when the cube is heated from 19.0°C to 67.0°C? The l
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Answer:

The volume of an aluminum cube is 0.212 cm³.

Explanation:

Given that,

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linear expansion coefficient \alpha=23.0\times10^{-6}/C^{\circ}

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Using formula of  volume expansion coefficient

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Put the value into the formula

\beta=3\times23.0\times10^{-6}

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The change temperature of the cube is

\Delta T=T_{f}-T_{i}

Put the value into the formula

\Delta T=67-19 = 48^{\circ}C

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Using formula of increases volume

\Delta V=V\beta\Delta T

Put the value into the formula

\Delta V=64\times69\times10^{-6}\times48

\Delta V=0.212\ cm^3

Hence, The volume of an aluminum cube is 0.212 cm³.

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3 years ago
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Explanation:

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