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lyudmila [28]
2 years ago
6

Can you guys please help me on this one?​

Physics
2 answers:
____ [38]2 years ago
6 0

Answer:

Si: [Ne] 3s² 3p²

Ca: [Ar] 4s²

Fe: [Ar] 3d6 4s2.

LenKa [72]2 years ago
4 0

If the object is not at rest how?

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HACTEHA [7]

The volume of the object must be no larger than 11.15 m^3.

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

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This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

\rho = \frac{m}{V}

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m is the mass of the object

V is its volume

For the object in this problem, the mass is

m=1.115\cdot 10^4 kg

Therefore, we can re-arrange the equation to find its volume:

V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3

So, the volume of the object must be no larger than 11.15 m^3.

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8 0
3 years ago
If two objects of the same size move through the air at different speeds, which encounters the greater air resistance?a. The fas
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Option A is correct.

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Option A is correct. (The faster object encounters more resistance)

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i think that the answer is a)

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