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Ipatiy [6.2K]
3 years ago
5

A straight wire in a magnetic field experiences a force of 0.023 N when the current in the wire is 2.5 A. The current in the wir

e is changed, and the wire experiences a force of 0.058 N as a result. What is the new current
Physics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

The new current in the wire is 6.3 A.

Explanation:

Given that,

Force in a straight wire, F = 0.023 N

Current in the wire, I = 2.5 A

If new force is, F' = 0.058 N, we need to find the new current.

We know that, magnetic force is given by :

F=ilB\sin\theta

It is clear that force is directly proportional to electric current. So, we can say:

\dfrac{F}{F'}=\dfrac{I}{I'}

I' is new current

I'=\dfrac{IF'}{F}\\\\I'=\dfrac{2.5\times 0.058}{0.023}\\\\I'=6.3\ A

So, the new current in the wire is 6.3 A. Hence, this is the required solution.

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Calculate the weight of an object that has a mass of 100 kg on earth
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Answer:

W = 980 N

Explanation:

Weight = Mass x Gravity

Weight = (100kg) x (9.8\frac{m}{s^2})

Weight = 980 N

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The Sun is about 150 million km from earth. how long does it take light from the sun to reach earth? (Speed of light is 3x10^8m/
madam [21]

Time  =        (distance) / (speed)

Time  =  (150 x 10⁹ m) / (3 x 10⁸ m/s) =

                           50 x 10¹ sec  = 

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3 0
4 years ago
Which scientist was the first to put the sun at the center of the "universe"?
lesya692 [45]

Answer: C. Nicolas Copernicus

Explanation:

Copernicus's model of the universe (heliocentric theory) was refuting the long life geocentric theory (the Earth as the center of the universe) proposed by <u>Ptolemy</u> and accepted by the Catholic Church.

In this sense, <u>Ptolemy's model of the universe placed the Earth in the center of the known universe</u>, where our planet remains stationary while the other planets, the Moon and the Sun describe complicated orbits around it.

As Ptolemy was a respected astronomer and geographer, this idea was accepted for a long time, until Copernicus arrived with the new model.

6 0
3 years ago
Calculate work done by the electrostatic force to move the charge with the magnitude of 1nC between two points 2cm spaced, along
timurjin [86]

Answer:

work done is = 0

Explanation:

given data

distance = 2 cm

potential = 1 V

charge with magnitude = 1 nC

to find out

work done by the electrostatic force

solution

we know that at equipotential surface is that surface which have equal potential at each every point that we say

work done will be

work done = ∫dw

∫dw = \int\limits^v1_v2 {q} \, dv

here q is charge

so

net work done = q ( v2 - v1 )

and

so v2 = v1 = 0

so

work done is = 0

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A 15 cm length of wire is moving perpendicularly
Korvikt [17]

Answer: C or B

Explanation:

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3 years ago
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