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Vikentia [17]
3 years ago
13

Compare 9 X 10^4 and 5 X 10^3

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

Step-by-step explanation:

9×10^4 is 18 times larger than 5×10^3

9×10^4=90,000

5×10^3=5,000

90,000 is 18 times larger than 5,000

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4 years ago
In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will e
Olenka [21]

Answer:

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Flagged as future criminal

Event B: Commits a crime.

In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will eventually commit a crime.

This means that P(B) = \frac{100}{1000100} = 0.00009999

If a person is going to commit a crime, the Precogs identify that person correctly 99.999% of the time

This means that P(A|B) = 0.99999

Probability of being identified as a criminal:

0.99999 out of 0.00009999(identified and commits crime).

(1-0.99999) out of (1-0.00009999) (identifed and does not commits crime). So

P(A) = 0.99999*0.00009999 + (1-0.99999)*(1-0.00009999) = 0.000109988

What is the probability that a person flagged as a future criminal by the Precogs will actually commit a crime

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.00009999*0.99999}{0.000109988} = 0.9091

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime

5 0
3 years ago
What is the value of x?<br><br> 2<br> 3<br> 6<br> 7
Romashka-Z-Leto [24]

Answer:

x = 2

Step-by-step explanation:

By the property of intersecting chords outside of the circle.

EC  \times ED = EB \times  EA \\ (x + 4)(x + 4 + 1) = (x + 1)(x + 1 + 11) \\ (x + 4)(x + 5) = (x + 1)(x + 12) \\  {x}^{2}  + (4 + 5)x + 20 =  {x}^{2}  + (1 + 12)x + 12 \\ 9x + 20 = 13x + 12 \\ 9x - 13x = 12 - 20 \\  - 4x =  - 8 \\ x =  \frac{ - 8}{ - 4}  \\  \huge \red{ \boxed{x = 2}}

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4 years ago
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