Answer:
y = 4 or y = 6
Step-by-step explanation:
2log4y - log4 (5y - 12) = 1/2
2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms
log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms
log_4(y^2/(5y-12)) = log_4(2) remove logarithm
y^2/(5y-12) = 2 cross multiply
y^2 = 10y-24 rearrange and factor
y^2 - 10y + 24 = 0
(y-4)(y-6) = 0
y= 4 or y=6
If you have a graphing calculator one way to know you are right is put the left side in Y1 and the right side in Y2 then hit 2nd trace and intersection then find the intersection and the X value is your answer. If you don't have a graphing calculator then I'm sorry
The answer for the exercise shown above is the last option (Option D), which is:
D. log base 5 of 56
The explanation is show below:
1. You have the following logarithm expresssion:
<span>log5(4*7 )+log5(2)
</span>
2. By the logarithms properties, you can rewrite the logarithm expression as following:
log5(28)(2)
log5(56)
3. Therefore, as you can see, the answer is the option mention before.
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