Answer: C-N(Longest) > C=N > CN(C triple bond N, shortest)
Explanation: Bond length is the distance between nuclei of bonded atoms.
Bond energy is the which needs to break the bond.
And bond length is always inversily proportional to bond energy.
Larger the bond energy ,shorter the bond length
Answer:
proton and neutron in region one and electron orbiting in region two is the answer
the elasticity of gas particle collisions, there is no energy loss when the particles pass one another. Gases are composed of a very large number of small particles, which spread out and avoid contact with one another.
<h3>Which of the following gas postulates from the kinetic molecular theory best explains why pressure exists in gases?</h3>
As the quantity of gas particles in the container rises, so does the frequency of wall interactions and subsequently the pressure of the gas. The average kinetic energy of a gas particle is exclusively dependent on the temperature of the gas, says the theory's final postulate. As the volume of gas particles inside the container grows, more of them will collide with the walls, increasing the pressure and the frequency of collisions.
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The balance of forces allows to find the result for the question if the isotope of boron 9.99 una is stable:
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The boron isotope of mass 9.99 uma is unstable because the repulsive force increases.
The stability of atomic nuclei depends on the balance the force is electrostatic repulsion between the protons and the strong interaction of attraction.
One way to achieve this balance is to increase the separation of the protons with uncharged particles between them, the neutral ones, the strong interaction is of the same magnitude for protons and neutrons, therefore the repulsion is decreased and the strong attraction interaction is maintained. .
In the case of Boron, which has 5 protons, the stable structures have more atomistic 10 and 11 una, which is why it has 5 and 6 neutrons each. Therefore each proton has a neutrons next to it and in the other case a proton at the end has two neutrons, this causes the distance between the protons to increase, decreasing the electrostatic repulsion.
It indicates that we have a Boron nucleus of mass 9.999. The number of protons must remain fixed, therefore there are only 4 neutrons.
Consequently, some of the protons does not have a neutron next to it and can approach the other proton, therefore the electrostatic repulsion increases and the stability of the atom decreases.
In conclusion, using the balance of Forces we can find the result for the question if the isotope of boron 9.99 una is stable:
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The boron isotope of mass 9.99 amu is unstable because the repulsive force increases.
Learn more about nuclear stability here: brainly.com/question/897383
