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PolarNik [594]
2 years ago
13

QUICK! WHOEVER GETS CORRECT FIRST GETS BRAINLIEST AND 20 POINTS!

Mathematics
2 answers:
artcher [175]2 years ago
4 0

Answer:

8 fit by 3 fit

coz the base is the part which is at the bottom

Snowcat [4.5K]2 years ago
3 0

Answer: 24ft squared

Step-by-step explanation:

8x3 = 24

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Please help it’s finding sin C , cos C and tan C
Aloiza [94]

The given triangle has a right angle.

We use the mnemonics SOH-CAH-TOA.

1i) \sin C =\frac{Opposite}{Hypotenuse},\implies \sin C =\frac{30}{34},\implies \sin C =\frac{15}{17}

ii) \cos C =\frac{Adjacent}{Hypotenuse},\implies \cos C =\frac{16}{34},\implies \cos C =\frac{8}{17}

\tan C =\frac{Opposite}{Adjacent},\implies \tan C =\frac{30}{16},\implies \tan C =\frac{15}{8}

2. We want to find the hypotenuse.

We know an angle to be 23 degrees.

We were also given the side opposite to this angle to be 1200km.

Therefore we use the sine ratio.

6 0
3 years ago
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lesya [120]

Answer:

Hmmm not sure I can answer that but if you do ever have a question let me know! :)

Step-by-step explanation:

4 0
2 years ago
21b-32+7b-20b=?<br> Tell fast pls
madam [21]

21b-32+7b-20b=

21b + 7b - 20b - 32

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2 years ago
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Let V be the volume of the solid obtained by rotating about the y-axis the region bounded by y=√x and y=x^2. Find V either by sl
Ede4ka [16]

Answer:

The volume of the solid is 3\pi/10

Step-by-step explanation:

In this case, the washer method seems to be easier and thus, it is the one I will use.

Since the rotation is around the y-axis we need to change de dependency of our variables to have f(x)\rightarrow f(y). Thus, our functions with y as independent variable are:

x=\sqrt{y}\\ x=y^2

For the washer method, we need to find the area function, which is given by:

A=\pi\cdot [(\rm{outer\ radius)^2 -(\rm{inner\ radius)^2 ]

By taking a look at the plot I attached, one can easily see that for a rotation around the y-axis the outer radius is given by the function x=\sqrt{y} and the inner one by x=y^2. Thus, the area function is:

A(y)=\pi\cdot [(\sqrt{y} )^2-(y^2)^2]\\A(y)=\pi\cdot (y-y^4)

Now we just need to integrate. The integration limits are easy to find by just solving the equation \sqrt(y)=y^2, which has two solutions y=0 and y=1. These are then, our integration limits.

V=\pi\int_{0}^1 (y-y^4)dy\\ V=\pi (\int_{0}^1 ydy - \int_{0}^1 y^4dy)\\ V=\pi/2-\pi/5\\\boxed{V=3\pi/10}

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3 years ago
Michael has a drawer with 8 pairs of black socks and 12 pairs of white socks. Without looking he takes a white pair of socks out
Lesechka [4]
D because there are more pair of white socks than black socks
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