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3 years ago

Geometry work HELP ASAP trying to find the measure of a circumference!!

Mathematics

1 answer:

dusya [7]3 years ago

7 0

Answer:

65 degrees

Step-by-step explanation:

Since it is given that AB=DC

then we know that AO=DO and BO=CO because it is the radius of a same circle.

Hence the shapes are equal and thus DOC=65 degree as it serves as a corresponding angle to AOB

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In an endurance race, Rachel ran

Reil [10]

Answer:

$31\frac{1}{5}\ miles$

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

The distance is equal to multiply the speed by the time

we have

$speed=9\frac{3}{5}\ \frac{miles}{hour}$

$time=3\frac{1}{4}\ hours$

$distance=(9\frac{3}{5})(3\frac{1}{4})$

Convert mixed number to an improper fraction

$9\frac{3}{5}=9+\frac{3}{5}=\frac{9*5+3}{5}=\frac{48}{5}$

$3\frac{1}{4}=3+\frac{1}{4}=\frac{3*4+1}{4}=\frac{13}{4}$

substitute

$distance=(\frac{48}{5})(\frac{13}{4})=\frac{624}{20}=31,2\ miles$

Convert to mixed number

$31.2\ mi=31+0.2=31+\frac{1}{5}=31\frac{1}{5}\ miles$

3 0

3 years ago

Let n be the product of the two smallest 3-digit prime numbers. Find the sum of the digits of n.

lilavasa [31]

Answer:

Step-by-step explanation:

n = 101 × 103 = 10,403

sum of digits = 8

7 0

3 years ago

What is the total area of each garden bed has a length of 4 feet Amelia

trasher [3.6K]

64 feet squared because 4 cubes

5 1

3 years ago

Read 2 more answers

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

3 0

3 years ago

Drew has two cats. One cat weighs 17 pounds, and the other one weighs 12 1/2 pounds. Audrey’s dog weighs 33 pounds. What is the

Step2247 [10]

Answer: 3.5 pounds

Step-by-step explanation:

17+12.5=29.5

33-29.5=3.5

4 0

3 years ago