Answer: The correct answer is "Instrument A is placed closer to Sam than instrument B".
Explanation:
The sound can be soft or loud. Loudness depends on the amplitude of the sound wave. Higher the amplitude, more will be loudness. Lower the amplitude, lesser will be loudness.
Pitch depends on the frequency.
In the given problem, the instruments A and B generate sound waves of the same amplitude and at the same time.
Loudness depends on the sound energy produced as the energy of the sound is directly proportional to the square of the amplitude. It also depends on the distance between the source and the receiver.
Sam records a louder sound from instrument A than from instrument B. It means that there is mismatch in loudness. It can happen due to the placement of the instrument A closer to Sam than instrument B.
Therefore, the correct option is "Instrument A is placed closer to Sam than instrument B".
Answer:
the answer is probably most likely D first and if thats incorrect than its B
♡ <em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>♡</em>
Answer:
A) conductors
Explanation:
A conductor can be defined as any material or object that allows the free flow of current or electrons (charge) in one or more directions in an electrical circuit. Some examples of a conductor are metals, tungsten, copper, aluminum, iron, graphite, etc.
Basically, the main purpose of a conductor in physics is to provide a low-resistance path between electrical circuits or components. This low-resistance path is to ensure that the electrical components allows the free flow of electrons and thus, enabling charge transfer.
Hence, the electrons in conductors move about more freely than the electrons in insulators which is why this type of material can be used to create electric circuits because it would significantly provide a low-resistance path between the electric circuits.
Answer:
Δλ = 3*10⁻³ m.
Explanation:
- At any wave, there exists a fixed relationship between the speed of the wave, the wavelength, and the frequency, as follows:
where v is the speed, λ is the wavelength and f is the frequency.
- Rearranging terms, we can get λ from the other two parameters, as follows:
- Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:
- The difference between both wavelengths, is just the difference between (3) and (4):
⇒ Δλ = 3*10⁻³ m.