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adoni [48]
3 years ago
12

A particle with an initial linear momentum of 2.00 kg-m/s directed along the positive x-axis collides with asecond particle, whi

ch has an initial linear momentum of4.00 kg-m/s, directed along the positive y-axis. The finalmomentum of the first particle is 3.00 kg-m/s, directed45.0?Above the positive x-axis. Find the final momen -tum of the second particle.
Physics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

Explanation:

We shall apply conservation of momentum along x and y axis.

Let the final momentum of second particle be p₁ along x axis and p₂ along y axis.

Considering momentum along x axis

2 + 0 = 3 cos 45 + p₁

p₁ = 2-2.12 = - 0.12 kg m/s

Considering momentum along y axis

4 + 0 = 3 sin 45 + p₂

p₂ = 4-2.12 = 1.88  kg m/s

Final momentum = √ ( p₁² + p₂² )

=√ ( .12² + 1.88² )

= 1.88 approx

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Answer:

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t²=124.49s²

t=11.16 s

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R=v₁t

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Answer:

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The relationship between potential difference and electric field strength for a uniform field is given by the equation

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In this problem, we have:

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