Answer:
The magnitude of the electric flux is 
Explanation:
Given that,
Electric field = 2.35 V/m
Angle = 25.0°
Area 
We need to calculate the flux
Using formula of the magnetic flux
Where,
A = area
E = electric field
Put the value into the formula
Hence, The magnitude of the electric flux is
Answer:
2
Explanation:
BRAINLIEST?? AND THANK ME LATER!!! HOPE THIS HELPED!!!
Answer:
The cannon has an initial speed of 13.25 m/s.
Explanation:
The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;
R = u
Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.
R = 26.3 m, H = 19.3 m, g = 9.8 m/
.
So that:
26.3 = u
= 
x 
691.69 = x
= 
= 
= 175.6104
⇒ u = 
= 13.2518
u = 13.25 m/s
The initial speed of the cannon is 13.25 m/s.
Answer:
1. SG
true
=2.689
2. The object is probably some sort of minerals and rocks such as Feldspar, Corals, Beryl, etc.
Explanation:
Given:
mass in the air= 0.0675 kg
mass in water= 0.0424 kg
Answer:
t = Δa / v
Explanation:
To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:
Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:
Acceleration = change in velocity / time
a = Δv / t ..... (1)
But
Δv = v₂ – v₁
Substitute the value of Δv into equation (1)
a = Δv / t
a = v₂ – v₁ / t ....... (2)
From equation (1), make Δv the subject of the equation.
a = Δv / t
Cross multiply
Δv = at .... (3)
From equation (1), make t the subject of the equation.
a = Δv / t
Cross multiply
at = Δv
Divide both side by a
t = Δv /a ...... (4)
From circular motion, centripetal's force is given by:
F = mv²/r
F = ma꜀
Therefore,
ma꜀ = mv²/r
Cancel out m
a꜀ = v²/r
SUMMARY:
a = Δv / t
a = v₂ – v₁ / t
Δv = at
t = Δv /a
a꜀ = v²/r
Considering the options given in question above, t = Δa / v is not a true statement.
