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Tresset [83]
2 years ago
5

A projectile is fired from the ground at a velocity of 30.0 m/s, 35.0 º from the horizontal. What is the maximum height the proj

ectile reaches in the air? How far away from the point it was fired does it hit the ground? What is the time the projectile is in the air?
Physics
1 answer:
Norma-Jean [14]2 years ago
8 0

Answer:

Vy = V sin theta = 30 * ,574 = 17.2 m/s

t1 = 17.2 / 9.8 = 1.76 sec to reach max height

Max height = 17.2 * 1.76 - 1/2 * 4.9 * 1.76^2 = 15.1 m

H = V t - 1/2 g t^2 = 1.2 * 9.8 * 1.76^2 = 15.1 m

Time to fall from zero speed to ground = rise time = 1.76 sec

Vx = V cos 35 = 24.6 m / sec     horizontal speed

Time in air = 1.76 * 2 = 3.52 sec before returning to ground

S = 24.6 * 3.52 = 86.6 m

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Answer:

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b) The drag force is:

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3 years ago
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Answer:

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Explanation:

Given Data

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falls=49.8 m

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Solution

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