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3 years ago

8

Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between

the plates is 1.2x10^-7 . Calculate the strength of the electric field between the plates

1 answer:

Romashka [77]3 years ago

6 0

Answer:

50,000 V/m

Explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

$\Delta V=Ed$

where

$\Delta V$ is the potential difference

E is the magnitude of the electric field

d is the distance between the plates

In this problem, we have:

$\Delta V=750 V$ is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

$E=\frac{\Delta V}{d}=\frac{750}{0.015}=50,000 V/m$

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