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Svetlanka [38]
3 years ago
14

If 3 bars of chocolate cost $15.00 ghana cedis how much will 7 bars cost ratio

Mathematics
1 answer:
Rudiy273 years ago
6 0

Answer:

7 chocolate bars will cost $35

Step-by-step explanation:

if 3 cost $15 then 1 bar would cost 5 dollars and 5x7=35

here is a ratio:

<u>3</u> = <u>7</u>

15 = 35

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The graph at the right described the money two clubs are earning from fundraising. In how many weeks will the two clubs have the
pickupchik [31]

Answer:

52 weeks

Step-by-step explanation:

The club starting with $270 (club 1) is increasing their bank balance each week by ...

... $280 -270 = $10

The club starting with $10 (club 2) is increasing their bank balance each week by ...

... $25 -10 = $15

Club 2 is gaining on Club 1 by $15 -10 = $5 each week. So, the initial difference of $270 -10 = $260 will be overcome in ...

... $260/($5/week) = 52 weeks

_____

The same result is shown in the attached graph, which also shows that both clubs' bank balances will be $790 at that time.

7 0
3 years ago
Please help quickly as possible please
zheka24 [161]
First we need to establish the fact that angles on a straight line ALWYS add up to 180
So, we solve the equation for x which turns out to be 3
But,were not done. The question asks us to find the value of the angle BOC
so we substitute the value of x into the equation for BOC (which is 6x+29)
And then your answer is 47 degrees

7 0
3 years ago
Can anyone help me with this question ?
SashulF [63]
88.75 for each shirt
3 0
3 years ago
Read 2 more answers
What is the value of x when -8 x - (8x) = -48?
Simora [160]

Answer:

x=3

Step-by-step explanation:

-8x-(8x)=-48

-8x-8x=-48

Collect like terms

-16x=-48

Divide both sides by-16

x=3

3 0
3 years ago
The radius of a nitrogen atom is 5.6 × 10^-11 meters, and the radius of a beryllium atom is 1.12 × 10^-10 meters. Which atom has
Airida [17]
The answer is Beryllium atom has a larger radius by 2 times.

Nitrogen atom: 5.6 × 10⁻¹¹ = 5.6 × 10⁻¹⁻¹⁰ = 5.6 × 10⁻¹ × 10⁻¹⁰ = 0.56 × 10⁻¹⁰
Beryllium atom: 1.12 × 10⁻¹⁰

Since 1.12 is bigger than 0.56, then the radius of beryllium atom is larger of the radius of nitrogen atom. Let's see by how many times:
1.12 × 10⁻¹⁰ : 0.56 × 10⁻¹⁰ = 1.12 : 0.56 = 2

4 0
3 years ago
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