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3 years ago

OAB is a sector of a circle with centre O and radius 8 cm.

Mathematics

1 answer:

max2010maxim [7]3 years ago

4 0

Answer:

The perimeter of the sector is :30.5 cm

Step-by-step explanation:

Mathematically, we have the area of the sector as;

e/360 * pi * r^2

r is 8 cm

so we have

58 = e/360 * pi * 8^2

58/64 * 360/pi = e

e = 103.85

To get the perimeter,

we have length of the arc plus 2r

Length of the arc is;

e/360 * 2 * pi * r

add 2 r;

e/360 * 2 * pi * r + 2r

so we have

103.85/360 * 2 * pi * 8 + 2(8)

= 14.5 + 16

= 30.5 cm

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What is the length of the hypotenuse of the triangle ?

Shkiper50 [21]

Answer:

The length of the hypotenuse of the triangle is about 14.14 units.

Step-by-step explanation:

You can determine this by using the Pythagorean Theorem.

a^2 + b^2 = c^2

To find the hypotenuse, take sides a and b (10 and 10) and square them. You get 100. When you add 100 and 100 together, you get 200, which equals c^2. Find the square root of 200 to find the hypotenuse.

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4 years ago

Read 2 more answers

Which of the following is equivalent to 2^2/5?

pashok25 [27]

The answer is letter A since the mixed form of 7/5 is equal to 1 and 2/5.

3 0

3 years ago

Evaluate the following when a= 1 ,b=3,and c =27 ( a) 6a^2+ 2bc-2c^1/3

Dennis_Churaev [7]

Answer:

6a^2+ 2bc-2c^1/3 <u>= 162</u>

Step-by-step explanation:

a = 1
b = 3
c = 27

$\rm 6 {a}^{2} + 2bc - 2 {c}^{ \frac{1}{3} }$

$= 6 {(1)}^{2} + 2(3)(27) - 2( {27)}^{ \frac{1}{3} }$

$\rm = 6 + 162 - 2 ( \sqrt[3]{27} )$

$\rm = 168 - 2(3)$

$\rm = 168 - 6$

$\boxed{\rm = 162}$

5 0

3 years ago

PLEASE HELP

larisa [96]

Answer:

1.) not safe

2.)

$18 \sqrt{3}$

Step-by-step explanation:

1.) given the length of the ladder = 15ft.

and the height to the top of ladder when leaned against a wall is 14.8ft. This all forms a right triangle.

with what we are given we can solve for the angle it creates from the ground to the leaned ladder by using the SOHCAGTOA. Whike we do this keep in mind its not safe for a ladder to create an angle more than 70 degrees.

in this case if we are solving for the angle where the height is opposite we will use SOH. because we know the oposite and the hyp. Sin(theta) = opp/hyp

$\sin(theta) = \frac{14.8}{15}$

$sin^{ - 1} ( \frac{14.8}{15} ) = 81 \: degrees$

therefore not safe.

2.)

your givin 90 and 60. remember all interior angles add up to 180.

therefore 30 would be the unknown angle.

knowing that we use the <u>chart</u> at the top.

across from 30 is 6. so we put that by x. (remember we are doing this to find the height for our area of a triangle formula = base time height devide by 2.)