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3 years ago

OAB is a sector of a circle with centre O and radius 8 cm.

Mathematics

1 answer:

max2010maxim [7]3 years ago

4 0

Answer:

The perimeter of the sector is :30.5 cm

Step-by-step explanation:

Mathematically, we have the area of the sector as;

e/360 * pi * r^2

r is 8 cm

so we have

58 = e/360 * pi * 8^2

58/64 * 360/pi = e

e = 103.85

To get the perimeter,

we have length of the arc plus 2r

Length of the arc is;

e/360 * 2 * pi * r

add 2 r;

e/360 * 2 * pi * r + 2r

so we have

103.85/360 * 2 * pi * 8 + 2(8)

= 14.5 + 16

= 30.5 cm

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ICE Princess25 [194]

The answer is 4

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8 0

3 years ago

Read 2 more answers

Susan has 343 cookies. She packs as many of them as she can equally in 19 boxes. She gives the rest to Mike. How many cookies do

Oksana_A [137]

Answer:

Mike gets just one cookie because she puts 18 cookies in 19 box which will be 19*18 = 342 so just one left

Step-by-step explanation:

I'm feeling bad for Mike to be honest that he just gets one

5 0

2 years ago

The cost to rent a car is $25 plus an additional $0.15 for each mile the car is driven. Which of the following equations could b

Nastasia [14]

Answer:

0.15m+25=c

replace c with 71.50

the third one

25+0.15m=71.8

3 0

3 years ago

Read 2 more answers

Please help me!!! Will get brainliest!!!

jek_recluse [69]

The answer is B because r is negative and less than the critical value.

7 0

3 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0

2 years ago