Given:
D be the event that a randomly chosen person has seen a dermatologist.
S be the event that a randomly chosen person has had surgery for skin cancer.
To find:
The correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist.
Solution:
Conditional probability: Probability of A given B is:

Let D be the event that a randomly chosen person has seen a dermatologist.
Let S be the event that a randomly chosen person has had surgery for skin cancer.
Using the conditional probability, the correct notation for the probability that a randomly chosen person has had surgery for skin cancer, given that the person has seen a dermatologist is P(S|D).
Therefore, the correct option is D.
Answers:
8. 12x+3= 27
move 3 to the other side , sign changes from +3 to -3
12x+3-3=27-3
12x= 24
divide by 12 for both sides
12x/12=24/12
x= 2
9. 6(y-10)=42
mutiply the bracket by 6
(6)(y)(6)(-10)= 6y-60
6y-60= 42
move -60 to the other side, sign changes from -60 to +60
6y-60+60=42+60
6y=102
divide by 6
6y/6=102/6
y=17
10. 9x-2=4x+13
move +4x to the other side
9x-4x-2= 4x-4x+13
5x-2= 13
5x-2+2= 13+2
5x= 15
divide by 5 for both sides
5x/5= 15/5
x= 3
11. 4/3y+5/2y= 1
find the common denominator for both of the fractions which is 6.
Mutiply by 2 for 4/3y .
4(2)/3(2)y=8/6y
Mutiply by 3 for 5/2y
5(3)/2(3y)= 15/6y
8/6y+15/6y= 23/6y
23/6y= 1
Mutiply both sides by 6/23
23/6y(6/23)= 1 (6/23)
Cross out 6 and 6 , divide by 6 and then becomes 1.
Cross out 23 and 23, divide by 23 and then becomes 1.
1*1*y=y
y= 6/23
Answer:
7.2 years
Step-by-step explanation:

where f(t) is the length and t is the number of years old
given the Mike measures 148 cm, we need to find out the age
So we plug in 148 for f(t) and solve for t

divide both sides by 200

Now subtract 1 from both sides

Divide both sides by -0.956

Now take ln on both sides



divide both sides by -0.18
t=7.2
So 7.2 years
Number six question is answers “Mid point”
Answer:
what is the question
Step-by-step explanation: