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Law Incorporation [45]
3 years ago
15

Write any two use of computer in school​

Computers and Technology
1 answer:
igomit [66]3 years ago
7 0

Answer:

To solve mathmatical problem

To make questions paper

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A chart and a graph are kind of image that are indispensable and need added text to go with it.

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A user is trying to log into windows on her notebook computer. she enters the correct password for her user account, but the sys
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If your body were a house, your skeleton would be the house's ___________.
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Which internetworking device makes computers that are connected to separate segments appear and behave as if they're on the same
Temka [501]

NIC Ports use which RJ connector? RJ-45 internetworking device makes computers that are connected to separate segments appear and behave as if they're on the same segment.

There's a lot of confusion out there about which NIC ports use which RJ connectors. RJ-45 internetworking devices make computers that are connected to separate segments appear and behave as if they're on the same segment. So, which one do you use?

The answer is actually quite simple. If you're connecting two computers together, you'll need to use an RJ-45 cable. If you're connecting a computer to a modem or router, you'll need to use an RJ-11 cable.

RJ-45 cables are actually quite common and can be found at most electronics stores. If you're not sure which one you need, just ask a sales associate for help.

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3 0
2 years ago
Show how the value 0xabcdef12 would be arranged in memory of a little-endian and a big-endian machine. Assume the data is stored
viva [34]

Answer and Explanation:

For the Big Endian

In a big endian format, the most significant byte is stored at the lowest address and the least significant byte is stored at the highest address. Therefore, the data given is stored as follows:

Address 0 | 1 | 2 | 3

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For the Little Endian

In a little endian format, the most significant byte is stored at the highest address (so the least significant byte is stored at the lowest address).

So, the data given would be stored as follows:

Address 0 | 1 | 2 |3

Byte 12 | ef | cd | ab

Hope this Helps!!!

5 0
3 years ago
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