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labwork [276]
2 years ago
6

POINTS! POINTS! ILL MAKE U BRAINLIST TOO :(

Mathematics
1 answer:
Over [174]2 years ago
4 0

Answer:

√12 then √ 26 then √48 then √63 then √99

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Please help me do the equation and figure out the right solution. I am supposed to be correcting the one in the picture.
alexira [117]

Answer:

The correct answer is if you want no roots in the denominator, the correct answer is \frac{2x}{y}* \sqrt[3]{2y^{2} }

Step-by-step explanation:

The mistake is that you can't take a cube root of a square at step 3 when y^{2} is taken out.

5 0
2 years ago
Express the form 1: n <br><br> 5:20
Stella [2.4K]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

5 : 20

Divide both sides by 5 to get the answer

5/5 = 1

20/5 = 4

Thus, the answer is 1 : 4

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

8 0
3 years ago
I have like 20 minutes please help<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D-7x%2B10%3D0" id="TexFormula1" title="x^{2}-7x+10
Mandarinka [93]

Answer: Hmm Ok i do this-

Step-by-step explanation:

Wait are we trying to find x?

Ok so for the first one x = 5 and for the second one x = 2

3 0
3 years ago
Use the function below to find F(3).
Vaselesa [24]
<span>F(x) = (1/4)^x

</span><span>F(3) = (1/4)^3 = 1/64

</span><span>B. 1/64</span>
8 0
3 years ago
Read 2 more answers
what is the sum of the first five ferms of a geometric series with a1=10 and r=1/5? express your answer as an important fraction
mote1985 [20]
The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number

Here you are given a=10 and r=1/5 so your equation is:

s(n)=10(1-(1/5)^n)/(1-1/5)  let's simplify this a bit:

s(n)=10(1-(1/5)^n)/(4/5)

s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:

s(5)=12.5(1-(1/5)^5)

s(5)=12.496

as an improper fraction:

(125/10)(3124/3125)

390500/31240

1775/142
6 0
3 years ago
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