Answer:
![y = -8x + 3](https://tex.z-dn.net/?f=y%20%3D%20-8x%20%2B%203)
Step-by-step explanation:
- Firstly, plug in the point and slope into the slope-intercept equation format:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
When lines are parallel to one another, their slopes are the same. But they have different y-intercepts. To explain further, slope is the angle of measure of a line from a horizontal standpoint and knowing that parallel angles must have the same angle, it can be concluded that parallel lines would have the same slope or in other words, an equal slope.
Now solving, use algebraic concepts:
11 = -8(-1) +b (Now solve for b)
11 = 8 + b (Subtract 8 from both sides) (Use the "Right" to "Left")
-8 -8
3 = b (Switch terms)
b = 3
Now let's write the equation with only slope and y-intercept.
Getting the result of:
y = -8x + 3
Answer:
1/18
Step-by-step explanation:
the common denominator is 18 which changed the problem to 9/18-8/18 which is 1/18
hope this helps!
The correct answer that i got would have to be 4,000
Answer:
x= 127
w = 53
Step-by-step explanation:
Answer: 46 square units
Step-by-step explanation:
First divide the given polygon by joining FS in triangle FNS and rectangle WFSC.
In triangle FNS, construct a line from N (2,4) to its base at (2,-2) and name it point O.
Since it is perpendicular to the base of the triangle therefore, it is the height of the triangle.
Now, by distance formula,
![NO=6\ units\\FS=9\ units](https://tex.z-dn.net/?f=NO%3D6%5C%20units%5C%5CFS%3D9%5C%20units)
Area of triangle =![\frac{1}{2}\times base\times height=\frac{1}{2}\times6\times9=27\ units^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20height%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes6%5Ctimes9%3D27%5C%20units%5E2)
Now, in Rectangle WFSC by the distance formula
WF=CS=2 units, FS=WC=9 units
Area of rectangle=![2\times9=18\ units^2](https://tex.z-dn.net/?f=2%5Ctimes9%3D18%5C%20units%5E2)
Now, Area of polygon WFNSC= area of triangle +area of rectangle
=27+18=46 square units