Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
It's C ray AC because it's the same length just opposite
Use the factor theorem to determine whether the first polynomial is a factor of the second polynomial x-3;2x^2-4x+30
x−3,2x^2−4x+30
So I believe you will have to do 10% x 7 as it has been seven years which will be 70% and 70% of 8000 is 5600 so the answer will be £5600
