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IrinaK [193]
3 years ago
15

Someone Help please!

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
What question do we need to solve??
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What are the discontinuities of the function f(x) = the quantity of x squared plus 2 x minus 24, all over 6 x plus 24.?
noname [10]
The discontinuities are x=-4. Because it is a fraction, you cannot divide by zero so if the denominator is set to equal zero, which it will if x=-4, the function will be be undefined
4 0
3 years ago
Rewrite 81 as 3 to some power.
NikAS [45]
First, let's find all the factors of 81:

81/3=27
27/3=9
9/3=3
3/1=1

So the factors of 81 are 3,3,3,3, (the numbers by which we divided here).

This means we can write down 81 as 3*3*3*3 or 3^{4} - which is the answer to the question! (three to the power of 4)
5 0
3 years ago
Select the number line model that matches the expression 1/4 - 5/4
Yuri [45]

Answer:

The answer would be -5/4

3 0
3 years ago
Emily purchased lemons for $600. She sold 3/4 of these at a loss of 20% and the remaining at a gain of 20%. How much percent doe
MAVERICK [17]

Answer:

10%

Step-by-step explanation:

Given: CP of lemon is $600.

           3/4 of lemon sold at 20% loss

           Remaining lemon at 20% gain.

Considering the quantity of lemon remain constant.

Cost price of 3/4 of lemon= \frac{3}{4} \times 600= \$450

As given, 3/4 of lemon sold at 20% loss.

∴ Selling price of \frac{3}{4}\ of\ lemon=  450- \frac{20}{100}\times 450

Selling price= 450- 90= \$ 360

Hence, selling price of 3/4 lemon is $360.

Now, the cost price of remaining lemon (1-\frac{3}{4} )= (\$ 600-\$ 450)

∴ The cost price of \frac{1}{4}\ lemon = \$ 150

As given, remaining \frac{1}{4} lemon\ sold\ at\ gain\ of\ 20\%

∴ Selling price of \frac{1}{4} \ lemon= (150\times \frac{20}{100}+150)

Selling price of \frac{1}{4} \ of\ lemon= (30+150)

Hence, selling price of 1/4 lemon is $180

Loss\profit percent= \frac{(SP-CP)}{CP} \times 100

∴ Loss\profit percent= \frac{60}{600} \times 100= 10\%

Hence, the loss percentage is 10%

8 0
3 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
2 years ago
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